Question

Can someone please help me with this I need help finding x and y using special right triangles and if you could please explain how

Answer 1

Answer:

y=46.445

x=24.04

Step-by-step explanation:

rule for first triangle which is  right isosceles triangle with angles 30-60-90

sin 30 = opp/hypt.

0.5= opp/34

opp=17 which is the height

the part of y in the first triangle = a^2+b^2=c^2

a^2= 17^2 , b^2=y , c^2 =34

y ( first triangle )= √867=29.445

second triangle is right angle triangle 45-90-45

x= 24.04

sin 45= opp/hypt.

1/√2 =17/x

x= 17*√2 = 24.04

solving for other part of y in the right triangle

h= y = 17

the whole base y= 29.445+17 = 46.445