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Gwar [14]
3 years ago
12

When dividing each of the numbers $$3759$$ and $$4139$$ by some positive integer number, the remainder happened to be equal to $

$16$$. What is the smallest possible value of the divisor?
Mathematics
1 answer:
Sedaia [141]3 years ago
3 0

Answer:

The smallest possible value of the divisor is 19

Step-by-step explanation:

The given numbers for division are;

3759 and 4139, the remainder = 16

Let x represent the number

Therefore, we have;

x > 16

x is a factor of 3759 - 16 = 3743, and x is also a factor of 4139 - 16 = 4123

The factors of 3743 obtained from an online resource are 1, 19, 197, 3759

The factors of 4123 obtained from an online resource are 1, 7, 19, 31, 133, 217, 589, 4123

The common factors of 3743 and 4123 are 1, 19

Given that x > 16, we have, x = 19

Therefore, the smallest possible value that will divide both 3759 and 4139 whereby the remainder is 16 = 19

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Calculate what 12% is out of 190.40

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A random sample of 40 binomial trials resulted in 14 successes. test the claim that the population proportion of successes does
mylen [45]

Using the z-distribution, since the p-value of the test is of 0.057 > 0.05, there is not enough evidence that the population proportion of successes does not equal 0.50.

<h3>What are the hypotheses tested?</h3>

At the null hypotheses, we test if the proportion of successes equals 0.5, hence:

H_0: p = 0.5

At the alternative hypotheses, we test if it does not equal, hence:

H_1: p \neq 0.5

<h3>What is the test statistic?</h3>

The test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

In which:

  • \overline{p} is the sample proportion.
  • p is the proportion tested at the null hypothesis.
  • n is the sample size.

For this problem, the parameters are given by:

n = 40, \overline{p} = \frac{14}{40} = 0.35, p = 0.5

Hence the test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

z = (0.35 - 0.5)/(0.5/sqrt(40))

z = -1.9.

<h3>What is the decision?</h3>

Using a z-distribution calculator, considering a two-tailed test, as we are testing if the proportion is different of a value, with z = -1.9, we get that the p-value of the test is of 0.057.

Since the p-value of the test is of 0.057 > 0.05, there is not enough evidence that the population proportion of successes does not equal 0.50.

More can be learned about the z-distribution at brainly.com/question/16313918

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