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Svet_ta [14]
3 years ago
5

A fireworks company has two types of rockets called Zinger 1 and Zinger 2. The polynomial -16t^2+150t gives the height in feet o

f Zinger 1 at t seconds after launch. The polynomial: -16t^2 + 165t gives the height of Zinger 2 at t seconds after launch. If the rockets are launched at the same time and both explode 6 seconds after launch, how much higher is Zinger 2 than Zinger 1 when they explode?
Mathematics
1 answer:
Alisiya [41]3 years ago
7 0
The height of Zinger 1 after 6 seconds is given by the polynomial

-16 t^{2}+150t, for t = 6, 

so the height is -16 *6^{2}+150*6=-576+900=324  (feet)


The height of Zinger 2 after 6 seconds is given by the polynomial

-16 t^{2}+165t, for t = 6, 

so the height is -16 *6^{2}+165*6=-576+990=414  (feet)


At the moment the rockets explode, Zinger 2 is 414-324=90 (feet)

higher than Zinger 1.


Answer: 90 feet
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