I don't see an inequality, but I can tell you that the sign of the inequality is flipped whenever you multiply or divide by a negative number.
Answer:
have you tries adding them together?
Answer:
7 x 6 x 5 = 210
Step-by-step explanation:
its a combination's problem.
7 horses are eligible for first place.
6 of those are eligible for 2nd given that one of the 7 finished first.
similarly 5 of the remaining are eligible for 3rd place given 2 horses have taken the first 2 spots.
therefore 7 x 6 x 5 possible combinations = 210 combinations.
Answer:
Step-by-step explanation:
We need to solve 
We know that,
Using the above formula,
![(8m-3n)^2 - (4m+3n)^2=(8m)^2+(3n)^2-2(8m)(3n)-[(4m)^2+(3n)^2+2(4m)(3n)]\\\\=64m^2+9n^2-48mn-(16m^2+9n^2+24mn)\\\\=64m^2+9n^2-48mn-16m^2-9n^2-24mn\\\\=48m^2-48mn-24mn\\\\=48m^2-72mn](https://tex.z-dn.net/?f=%288m-3n%29%5E2%20-%20%284m%2B3n%29%5E2%3D%288m%29%5E2%2B%283n%29%5E2-2%288m%29%283n%29-%5B%284m%29%5E2%2B%283n%29%5E2%2B2%284m%29%283n%29%5D%5C%5C%5C%5C%3D64m%5E2%2B9n%5E2-48mn-%2816m%5E2%2B9n%5E2%2B24mn%29%5C%5C%5C%5C%3D64m%5E2%2B9n%5E2-48mn-16m%5E2-9n%5E2-24mn%5C%5C%5C%5C%3D48m%5E2-48mn-24mn%5C%5C%5C%5C%3D48m%5E2-72mn)
So, the final answer is .
Answer :
That’s it, the probability of getting tail on a single coin toss times the number of observations.
In this case, 1/2 * 72 = 36
However, there’s something called chance error. How much do you expect the result to differ from the expected value? It can be calculated as follows:
The Standard Deviation of this experiment is √(0.5)(0.5) =0.5
The Standard Error is √72 (0.5) ≈ 4.18330 round to the nearst tenth is 4
So, the expected value is 36, give or take 4.
And since the number of tails in a toss coin experiment is normally distributed, then you can expect the number of tails to be between -2 and +2 SEs from the expected value 95% of the time.
In other words, if you repeat this experiment a large number of times, you can expect to obtain between 27 and 43 tails 95% of the time.
Hope this helps
