X varies inversely with y and x = 8 when y = 10, what is the value of y when x=6
1 answer:
The right answer for the question that is being asked and shown above is that:
x = k (1/y)
k = xy
x1y1 = x2y2
8*10 = 6y2
80 = 6y2
y2 = 40/3
So the answer is 40/3
<span>X varies inversely with y and x = 8 when y = 10, what is the value of y when x=6</span>
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