The amount of balls in a given layer can be found by squaring the layer it is in
4 layers
top layer (1st) is 1
2nd is 4
3rd layer is 9
4th is 16
add them up
1+4+9+16=30
30 in that pyramid
A quick and easy way to do this particular question is to think all of these numbers are close to 1/2 except 2/31. So, the lowest is 2/31.
H O P E T H I S H E L P S!
So distribute using distributive property
a(b+c)=ab+ac so
split it up
(5x^2+4x-4)(4x^3-2x+6)=(5x^2)(4x^3-2x+6)+(4x)(4x^3-2x+6)+(-4)(4x^3-2x+6)=[(5x^2)(4x^3)+(5x^2)(-2x)+(5x^2)(6)]+[(4x)(4x^3)+(4x)(-2x)+(4x)(6)]+[(-4)(4x^3)+(-4)(-2x)+(-4)(6)]=(20x^5)+(-10x^3)+(30x^2)+(16x^4)+(-8x^2)+(24x)+(-16x^3)+(8x)+(-24)
group like terms
[20x^5]+[16x^4]+[-10x^3-16x^3]+[30x^2-8x^2]+[24x+8x]+[-24]=20x^5+16x^4-26x^3+22x^2+32x-24
the asnwer is 20x^5+16x^4-26x^3+22x^2+32x-24
The answer is A 109
Explanation:
Solve for x when doing 6x+19=7x+4
Then plug in the value of x into 6x+19
Answer:
we conclude that when we put the ordered pair (0, a), both sides of the function equation becomes the same.
Therefore, the point (0, a) is on the graph of the function f(x) = abˣ
Hence, option (D) is correct.
Step-by-step explanation:
Given the function
f(x) = abˣ
Let us substitute all the points one by one
FOR (b, 0)
y = abˣ
putting x = b, y = 0
0 = abᵇ
FOR (a, b)
y = abˣ
putting x = a, y = b
b = abᵃ
FOR (0, 0)
y = abˣ
putting x = 0, y = 0
0 = ab⁰
0 = a ∵b⁰ = 1
FOR (0, a)
y = abˣ
putting x = 0, y = a
a = ab⁰
a = a ∵b⁰ = 1
TRUE
Thus, we conclude that when we put the ordered pair (0, a), both sides of the function equation becomes the same.
Therefore, the point (0, a) is on the graph of the function f(x) = abˣ
Hence, option (D) is correct.
