(A) For x representing the cost of one of Tanya's items, her total purchase cost 5x. The cost of one of Tony's items is then (x-1.75) and the total of Tony's purchase is 6(x-1.75). The problem statement tells us these are equal values. Your equation is ...
... 5x = 6(x -1.75)
(B) Subtract 5x, simplify and add the opposite of the constant.
... 5x -5x = 6x -6·1.75 -5x
... 0 = x -10.50
... 10.50 = x
(C) 5x = 5·10.50 = 52.50
... 6(x -1.75) = 6·8.75 = 52.50 . . . . . the two purchases are the same value
(D) The individual cost of Tanya's iterms was $10.50. The individual cost of Tony's items was $8.75.
Answer:
Simplifying 9m + -3 + -7m = 0
Reorder the terms: -3 + 9m + -7m = 0
Combine like terms: 9m + -7m = 2m -3 + 2m = 0 Solving -3 + 2m = 0
Solving for variable 'm'. Move all terms containing m to the left, all other terms to the right.
Add '3' to each side of the equation. -3 + 3 + 2m = 0 + 3 Combine like terms: -3 + 3 = 0 0 + 2m = 0 + 3 2m = 0 + 3 Combine like terms: 0 + 3 = 3 2m = 3
Divide each side by '2'. m = 1.5
Step-by-step explanation:
Hope this helps :)
<span>y=−1/3x+1
</span>x = -6, y = −1/3(-6) +1 = 3<span>
x = -3, y = </span>−1/3(-3) +1 = 2<span>
x = 0, y = 1
</span>x = 3, y = −1/3(3) +1 = 0
x = 6, y = −1/3(6) +1 = -1
<span>
Table
x y
-6 3
-3 2
0 1
3 0
6 -1
</span>
Answer:
The amounts of money each has are:
Joe = $92
Charlie = $29
Leila = $23
Step-by-step explanation:
To solve this, we will convert the statements into an equation, and use that to solve for the unknowns, as follows:
total amount = $144
Let Leila's share be S
Joe's share = 4 times Leila's = 4S
Charlie's share = $6 + Leila's share = 6 + S
Joe's share + Charlie's Share + Leila's Share = $144
4S + (6 + S) + S = 144
4S + 6 + S + S = 144
4S + 2S + 6 = 144
6S + 6 = 144
6S = 144 - 6 = 138
S = 138 ÷ 6 = $23
Therefore Leila's share 'S' = $23
Joe share= 4S = 4 × 23 = $92
Charlie's share = 6 + 23 = $29
