Question

Determine the number of possible positive and negative real roots; then use the rational root theorem to determine all of the possible roots of the equation: 4x^4+20x-2=0​

Answer 1

Answer:

+- 1/4,1/2,1,2,4

5 solutions.

Step-by-step explanation:

so first we have to do this using the theorum we find all the divors of -2

so +-2, +-1/ +-2,+-1,+-4 so there would be 5 solutions.

+- 1/4,1/2,1,2,4

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