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KATRIN_1 [288]
3 years ago
5

Between which two integers does 35 lie?

Mathematics
1 answer:
iren2701 [21]3 years ago
7 0

The answer is the first choice, "5 and 6."

The square root of 35 is equal to 5.92, which is in between the numbers 5 and 6.

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Help Please (I needed 20 characters)
liq [111]
Is a (0,18) ? not sure though baha.
4 0
3 years ago
Find MP………………………………….
devlian [24]

Answer:

MP = 29

Step-by-step explanation:

MP = 17 + 3y

5y + 9 = 17 + 3y

      -9    -9

5y = 8 + 3y

-3y        -3y

2y = 8

2y / 2 = 8 / 2

y = 4

MP = 17 + 3 (4)

MP = 29

5 0
1 year ago
Negative 7 bigger or smaller than negative 8
dalvyx [7]
-7 is bigger than -8          
4 0
3 years ago
Read 2 more answers
What is 2.75 rounded to the nearest hundredth
almond37 [142]
Well first off we need to know how to round or what rounding is. Rounding is the approximation of numbers usually decimals to a approximate cut off number for numbers that are too long or hard to work with/remember. To round a number you simply need to look at the number behind that number whether its a whole number (integer) or a decimal, either one will work. Now continuing on (on) how to round the number, look at the number after it and if it is 5 or above the number rounds up +1 and all numbers behind that turn to 0. For example 3.25500 round to the nearest hundredth, 3.26(000). Now if the number is 4 or smaller then you don't do anything at all (no rounding) and all the numbers after the being rounded number turn to 0's like so, 3.254(0000) rounded to the nearest hundredth, 3.25(00000). So now that we know how to round and what rounding is we need to look at are hundredth place on are number here and see what the next number is after that, in this case it is 0 because there is no stated number there the default next number is 0 like so,
2.750 and because 0 is under 5 we don't do any rounding at all here and just leave it as it is. So 2.75 rounded to the nearest hundredth is 2.75

Enjoy!=)
4 0
3 years ago
for a short time after a wave is created by wind the height of the wave can be modeled using y= a sin 2pit/T where a is the ampl
dangina [55]

Answer:

y = 4 sin(t/2 + 4π/3) − 2

Step-by-step explanation:

General form:

y = a sin(2π/T t)

Given a = 4 and T = 4π:

y = 4 sin(2π/(4π) t)

y = 4 sin(t/2)

Add horizontal shift of -4π/3 and vertical shift of -2:

y = 4 sin(t/2 − (-4π/3)) − 2

y = 4 sin(t/2 + 4π/3) − 2

6 0
3 years ago
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