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Lady_Fox [76]
3 years ago
7

Create a code for playing blackjack

Computers and Technology
1 answer:
Alex17521 [72]3 years ago
6 0

Answer:

import random

is_stay = 'n'

y_fcard = random.randint(1, 11)

y_scard = random.randint(1, 11)

d_fcard = random.randint(1, 11)

d_scard = random.randint(1, 11)

you_score = y_fcard + y_scard

dealer_s = d_fcard + d_scard

print("Your score", you_score)

print("dealer's score", dealer_s)

while is_stay == 'n':

   if you_score > 21:

       break

   you_score += random.randint(1, 11)

   print("Your score", you_score)

   is_stay = input("Do you want to stay y/n?: ")

   if you_score > 21:

       print("You lost")

       quit()

while dealer_s <= 16:

   dealer_s += random.randint(1, 11)

   if dealer_s > 21:

       print("The dealer lost")

       quit()

if you_score > dealer_s:

   print("You are the winner", "My score: ",you_score, "\nDealer's score: ", dealer_s)

else:

   print("Sorry, you lost the game", "My score: ",you_score, "\nDealer's score: ", dealer_s)

Explanation:

The python program uses the random module's 'randint' to get a random integer number between 1 and 11, and adds the value to the user's score if the user decides to hit but compares the result with the dealer's if the user stays.

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Answer:

if(isBalloon== true && isRed==false) //compare the value of isBalloon variable with true value and isRed variable value with false value.

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Explanation:

The "if-else" statement is defined above for the problem which is given on the question. The detailed explanation of the answer is described below--

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