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Leya [2.2K]
2 years ago
12

The current in a resistor is 5.0 A, and its power is 60 W. What is the voltage?

Computers and Technology
2 answers:
alexandr1967 [171]2 years ago
8 0

The voltage on a resistor will be "12 V".

According to the given question,

Current,

  • I = 5.0 A

Power,

  • P = 60

As we know the formula,

→ Power (P)= Current(I)\times Voltage (V)

or,

→              V = \frac{P}{I}

By putting the giving values, we get

→                  = \frac{60}{5}

→                  = 12 \ V

Thus the solution above is right.

Learn more about voltage here:

brainly.com/question/18883096

katrin [286]2 years ago
3 0

Explanation:

Applying Ohm's law, we have that the formula for power is a product of the current and voltage in the resistor.

P = I \times V

P = 60 W and I = 5.0 A

60 = 5  \times V

V = 60  \div  5

V = 12 V

Hope this helped!

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Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server
sattari [20]

Answer:

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<em />

Explanation:

Given

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Required

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------------------------------------------------------------------------------------------------

<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

p = 99.98\%

Recall that probabilities always add up to 1;

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p + q = 1

Subtract q from both sides

p + q - q = 1 - q

p = 1 - q

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p = 1 - q = 99.98\%

1 - q = 99.98\%

Let the number of servers be represented with n

The above expression becomes

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Convert percent to fraction

1 - q^n = \frac{9998}{10000}

Convert fraction to decimal

1 - q^n = 0.9998

Add q^n to both sides

1 - q^n + q^n= 0.9998 + q^n

1 = 0.9998 + q^n

Subtract 0.9998 from both sides

1 - 0.9998 = 0.9998 - 0.9998 + q^n

1 - 0.9998 = q^n

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0.0002 = 0.05^n

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Log(0.0002) = Log(0.05^n)

From laws of logarithm Loga^b = bLoga

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Divide both sides by Log0.05

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\frac{Log(0.0002)}{Log(0.05)} = n

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