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Leya [2.2K]
2 years ago
12

The current in a resistor is 5.0 A, and its power is 60 W. What is the voltage?

Computers and Technology
2 answers:
alexandr1967 [171]2 years ago
8 0

The voltage on a resistor will be "12 V".

According to the given question,

Current,

  • I = 5.0 A

Power,

  • P = 60

As we know the formula,

→ Power (P)= Current(I)\times Voltage (V)

or,

→              V = \frac{P}{I}

By putting the giving values, we get

→                  = \frac{60}{5}

→                  = 12 \ V

Thus the solution above is right.

Learn more about voltage here:

brainly.com/question/18883096

katrin [286]2 years ago
3 0

Explanation:

Applying Ohm's law, we have that the formula for power is a product of the current and voltage in the resistor.

P = I \times V

P = 60 W and I = 5.0 A

60 = 5  \times V

V = 60  \div  5

V = 12 V

Hope this helped!

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Following are the code to this question:

import random#import package for using random method  

def rolling_dice(): #defining method rolling_dice that uses a random number to calculate and add value in dice1 and dice2 variable

   dice1 = random.randint(1,6)

   dice2 = random.randint(1,6)

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def rolling(): # defining method rolling

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       d = rolling_dice()#defining d variable that hold method value

       n_roll+= 1 #defining n_roll that increment n_roll value by 1

       if d == 7 or d == 11:# defining if block that uses the d variable that checks either 7 or 11, player won d in p variable

           p+= d   # use p variable that adds d variable

       elif d == 2 or d == 3 or d == 12:#defining elif block to that checks d variable by using or operator  

           p-= d#defining d variable that decreases d variable variable

       else: # defining else block

           p1 = d # using p1 variable that store d value  

           while True:# defining loop that calculates values

               d = rolling_dice()#defining d variable that holds method values

               n_roll += 1 #increment the n_roll value by 1

               if d == 7:#defining if block that checks d value equal to 7

                   p -= p1#subtract the value of p1 in p variable  

                   break # exit loop

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                   break#using break keyword

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