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levacccp [35]
3 years ago
5

Hi... can you tell me is this formula is right or wrong?? ​

Mathematics
1 answer:
Llana [10]3 years ago
6 0

Answer:

this formula is right

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Helppp what’s the answer
jarptica [38.1K]

Answer:

It is the 3rd option (going from left to right)

Step-by-step explanation:

7 0
3 years ago
The population of rabbits on an island is growing exponentially. In the year 1995, the population of rabbits was 1000, and by 19
irakobra [83]

Answer:

3,240

Step-by-step explanation:

The computation of the population of rabbits in the year 2003 is shown below:

Given that

In the year 1995, the population of the rabbits was 1000

And, in 1999 the population of the rabbits grown to 1,800

So there is an increase of

= (1800 - 1000) ÷ 1000

= 80%

So for 2003, the population of the rabbits is

= 1800 + (1800 × 0.80)

= 3,240

4 0
3 years ago
Read 2 more answers
David and Eric each shot 6 arrows at the target shown. David shot 4 arrows into A and 2 into B. His score was 18 points. Eric sh
liq [111]
Lets write an equation for each guy's shots and score:
4A + 2B = 18
3A + 3B = 21
To solve we multiply the first equation by -3 and the second by 2:
-12A - 6B = -54
  6A + 6B = 42
--------------------
-12A + 0 = -12
A = 1
to find B we substitute in the first equation:
<span>4A + 2B = 18
</span><span>4(1) + 2B = 18
</span><span>4 + 2B = 18
</span>2B = 14
B = 7
therefore there were given 7 points in an arrow in B
3 0
3 years ago
(-2/3, sqrt5/3) is a point on a unit circle. Find the cosine, cosecant, and sine of the angle.
Nana76 [90]

Look at the picture.

\csc\theta=\dfrac{1}{\sin\theta}=\dfrac{1}{\frac{y}{r}}=\dfrac{r}{y}

We have the right triangle x, y and r. From the Pythagorean theorem we have:

r^2=x^2+y^2\to r=\sqrt{x^2+y^2}

We have the point

\left(-\dfrac{2}{3};\ \dfrac{\sqrt5}{3}\right)

Substitute:

r=\sqrt{\left(-\dfrac{2}{3}\right)^2+\left(\dfrac{\sqrt5}{3}\right)^2}\\\\r=\sqrt{\dfrac{4}{9}+\dfrac{5}{9}}\\\\r=\sqrt{\dfrac{9}{9}}\\\\r=1

\csc\theta=\dfrac{1}{\frac{\sqrt5}{3}}=\dfrac{3}{\sqrt5}=\dfrac{3\cdot\sqrt5}{\sqrt5\cdot\sqrt5}=\boxed{\dfrac{3\sqrt5}{5}}

8 0
3 years ago
Which goes to this inequality x + 1 &lt; 3
Serggg [28]
I got x < 2 for the inequality
Look at the image for more information

7 0
3 years ago
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