All categories

2 years ago

Hi... can you tell me is this formula is right or wrong??

Mathematics

1 answer:

Llana [10]2 years ago

6 0

Answer:

this formula is right

You might be interested in

What is the awnser to this question

Alborosie

Answer is A and C because they equal to 3(10-c)

4 0

2 years ago

4x + 7y = 12<br> -8x - 14y = -24

Masteriza [31]

Answer:

x = 3

y = 0

Step-by-step explanation:

4(3) + 7(0) = 12

-8(3) - 14(0) = -24

8 0

2 years ago

Find the length of MP. round to the nearest hundredth.

lozanna [386]

Answer:

Step-by-step explanation:

Use sine:

$sine=\dfrac{opposite}{hypotenuse}$

We have:

$opposite=MP\\hypotenuse=8.7\ cm\\\alpha=20^o\\\\\sin20^o\approx0.342$

Substitute:

$\dfrac{MP}{8.7}=0.342$

$\dfrac{MP}{8.7}=\dfrac{342}{1,000}$ <em>cross multiply</em>

$1,000MP=2975.4$ <em>divide both sides by 1,000</em>

$MP=2.9754\to MP\approx2.98$

6 0

2 years ago

What is the relationship between the 4s in the number 4498

algol13

The 4 in the thousands place is 10 times the 4 in the hundreds place.

7 0

3 years ago

Read 2 more answers

Plz help me with this

AnnZ [28]

Answer: $\bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}$

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, $B=\dfrac{6}{5}$ → $P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}$

Half of that period is: $\dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}$

Calculate the period for each of the options to find a match:

$A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}$

7 0

2 years ago

Hi... can you tell me is this formula is right or wrong?? ​

Hi... can you tell me is this formula is right or wrong??