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KonstantinChe [14]
3 years ago
13

3x3 - 7x2 + 6x - 14 Explain

Mathematics
2 answers:
bogdanovich [222]3 years ago
5 0

\huge\text{Hey there!}

\bold{Factor: 3x^3 -7x^2+6x -14}

\bold{Step-by-step\downarrow}

\bold{x^2(\dfrac{3x^3}{x^2}-\dfrac{7x^2}{x^2})+2(\dfrac{2\times3x}{2}-\dfrac{2\times7}{2})}

\bold{= x^2(3x^{3-2}-7)+2(3x-7)}

\bold{= x^2(3x-7)+2(3x-7)}

\bold{= (3x-7)(\dfrac{x^2(3x-7)}{3x-7}+\dfrac{2(3x-7)}{3x-7})}

\bold{= \underline{(3x -7)(x^2+2)}}

\boxed{\boxed{\bold{Answer: (x^2+2)(3x-7)}}}\huge\checkmark \underline\bold{(Option\ C.)}

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

mojhsa [17]3 years ago
3 0

Answer:

Step-by-step explanation:

x^2(3x - 7) + 2(3x - 7)

(x^2 + 2)(3x - 7)

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Andre ran 2 kilometers in 15 minutes, and Jada ran 3 kilometers in 20 minutes.
Vladimir79 [104]

Answer:

They do not run at the same rate because Jada ran at a rate of .150km per min, while Andre ran at .133333 km per minute.

Step-by-step explanation:

Andre ran : 2km/15min = .133333km per min

Jada ran: 3km/20min=.150km per minute

.150>.1333, so Jada ran at a higher rate of kilometers per minute.

8 0
4 years ago
At a store, Lauren selected a watermelon that weighed 38.4 ounces.
Mrrafil [7]

Answer:

$3.60

Step-by-step explanation:

1.50 ÷ 16 = 0.09375

there are 38.4 oz in laurens watermelon, so multiply the cost per ounce by the number of ounces to find the answer

0.09375 × 30.4 = 3.6

5 0
3 years ago
On a coordinate plane, 2 cube root functions are shown. Function f (x) goes through (negative 3, negative 1.5), has an inflectio
Strike441 [17]

Using translation concepts, it is found that the equation that represents the graph of g(x) is:

g(x) = \sqrt[3]{x + 2}.

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, we have that g(x) is a shift left of 2 units of f(x), hence:

  • f(x) = \sqrt[3]{x}
  • g(x) = f(x + 2) = \sqrt[3]{x + 2}

More can be learned about translation concepts at brainly.com/question/4521517

#SPJ1

5 0
2 years ago
1) UN MOVIL A SE MUEVE DESDE UN PUNTO CON VELOCIDAD CONSTANTE DE 20m/s EN EL MISMO INSTANTE A UNA DISTANCIA DE 1200m, OTRO MOVIL
alisha [4.7K]

Answer:

El móvil B necesita 60 segundos para alcanzar al móvil A y le alcanza una distancia de 2400 metros con respecto al punto de referencia.

Step-by-step explanation:

Supóngase que cada movil viaja en el mismo plano y que el móvil B se localiza inicialmente en la posición x = 0\,m, mientras que el móvil A se encuentra en la posición x = 1200\,m. Ambos móviles viajan a rapidez constante. Si el móvil B alcanza al móvil A después de cierto tiempo, el sistema de ecuaciones cinemáticas es el siguiente:

Móvil A

x_{A} = 1200\,m+\left(20\,\frac{m}{s} \right)\cdot t

Móvil B

x_{B} = \left(40\,\frac{m}{s} \right)\cdot t

Donde:

x_{A}, x_{B} - Posiciones finales de cada móvil, medidas en metros.

t - Tiempo, medido en segundos.

Si x_{A} = x_{B}, el tiempo requerido por el móvil B para alcanzar al móvil A es:

1200\,m+\left(20\,\frac{m}{s} \right)\cdot t = \left(40\,\frac{m}{s} \right)t

1200\,m = \left(20\,\frac{m}{s} \right)\cdot t

t = \frac{1200\,m}{20\,\frac{m}{s} }

t = 60\,s

El móvil B necesita 60 segundos para alcanzar al móvil A.

Ahora, la distancia se obtiene por sustitución directa en cualquiera de las ecuaciones cinemáticas:

x_{B} = \left(40\,\frac{m}{s} \right)\cdot (60\,s)

x_{B} = 2400\,m

El móvil B alcanza al móvil A a una distancia de 2400 metros con respecto al punto de referencia.

3 0
3 years ago
Brian rehr obtains an installment loan of 1250 to buy canoe requires 24 monthly payments and has an apr of 10%
Norma-Jean [14]

Answer:

I believe it is 122.6

Step-by-step explanation:

1,250 - 24 = 1,226

10%of 1,226 = 122.6

8 0
3 years ago
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