The function f(x) = 2x^2 + 3x + 5, when evaluated, gives a value of 19. What is the function’s input value?

1 answer:

3 0

$f(x)=19 \\
2x^2+3x+5=19 \\
2x^2+3x+5-19=0 \\
2x^2+3x-14=0 \\
2x^2-4x+7x-14=0 \\
2x(x-2)+7(x-2)=0 \\
(2x+7)(x-2)=0 \\
2x+7=0 \ \lor \ x-2=0 \\
2x=-7 \ \lor \ x=2 \\
x=-\frac{7}{2} \ \lor \ x=2$

The value of the function is 19 for x=-7/2 or x=2.
The answer is C.

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