The function f(x) = 2x^2 + 3x + 5, when evaluated, gives a value of 19. What is the function’s input value?

1 answer:

3 0

$f(x)=19 \\
2x^2+3x+5=19 \\
2x^2+3x+5-19=0 \\
2x^2+3x-14=0 \\
2x^2-4x+7x-14=0 \\
2x(x-2)+7(x-2)=0 \\
(2x+7)(x-2)=0 \\
2x+7=0 \ \lor \ x-2=0 \\
2x=-7 \ \lor \ x=2 \\
x=-\frac{7}{2} \ \lor \ x=2$

The value of the function is 19 for x=-7/2 or x=2.
The answer is C.

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Whats 3.2r + 14.7=6.74

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r=-199/80 is the right answer. First, you had to multiply by 100 from both sides of the equation. And it gave us, $3.2r*100+14.7*100=6.74*100$ . Next, you had to refine, and it gave us, $320r+1470=674$ . Then, subtract by 1470 from both sides of equation. And it gave us, $320r+1470-1470=674-1470$ . Simplify, and it gave us, $320r=-796$ . You can also divide by 320 from both sides of equation. And it gave us, $\frac{320r}{320}=\frac{-796}{320}$ . And finally, simplify, and it gave us the answer is r=-199/80 is the right answer. Hope this helps! And thank you for posting your question at here on brainly. And have a great day! -Charlie