Pls help me I’ll brainlest for the right answer plssss help I’m failing math grades close today

Why did large numbers of Africans migrate to the Americas? A. Countries competed over resources during the Age of Exploration, a

Marianna [84]

Answer:DEFINITELY B

THE PROOF IS IN YOUR BIBLE

Step-by-step explanation:

7 0

3 years ago

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

3 years ago

Need to keep cell bill under 60.,monthly charge is 30. And texts are 0.05 each. Write an inequality to represent the # of texts

nignag [31]

Answer:

$30 + 0.05x < 60$

The number of texts she can have is less than 600.

Step-by-step explanation:

Total monthly charge

30 + 0.05 for each text.

So, for x tests, the charge is:

$C(x) = 30 + 0.05x$

Write an inequality to represent the # of texts she can have?

It has to be under 60, so:

$C(x) < 60$

$30 + 0.05x < 60$

The solution is:

$0.05x < 30$

$x < \frac{30}{0.05}$

$x < 600$

The number of texts she can have is less than 600.

5 0

2 years ago

Write the equation of the line in slope-intercept form that goes through the points: (2, 4) and (7, -1) *

avanturin [10]

Answer:

1. slanting upward because the slope is positive one.

2. A: 3/4 B: 4/-3

3. A: 3 B: y=3x-10

1. (-2-7)/(-4-5) = -9/-9 = 1

2. A: (7-4)/(7-3) = 3/4

B: (8-0)/(-6-0) = 8/-6 = 4/-3

3. find the slope first so (4-1)/(2-1)= 3/1. then you plug in point C to find the y intercept so y=mx+b would be 2=3(4)+b which makes it so b is -10. the new equation would be y=3x-10

Step-by-step explanation:

4 0

2 years ago

The lengths of the sides of a square are represented by the expression 3x + 1 cm. The perimeter of the square is 28 cm. What is

pshichka [43]

Answer:

x=2

Step-by-step explanation:

Perimeter of a square = 4*(side of the square)

28 = 4*(3x+1)

28 = 12x + 4

28- 4 = 12x

24 = 12x

x =2

7 0

2 years ago