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Rina8888 [55]
2 years ago
14

Please answer all three questions Pleaseeeeee tysmm <3

Mathematics
1 answer:
oee [108]2 years ago
6 0

Answer: 2 3/4 > 2.68 is correct (only)

Step-by-step explanation: 2 3/4 = 2.75, and 2.75 is greater than 2.68

The rest are incorrect. 7.895 * 10^2 (100) = 789.5, and 5.43 * 10^3 (1000) = 5430. So 789.5 > 5430 is false.

Sqrt(63) = 7.93, and 7.93 > 8.11 is false.

Absolute values ( | | ) mean that no matter if it is negative or positive, it will become positive (unless the negative sign is outside the absolute value). 1.5 > 3.2 is false, and even without the absolute value, -1.5 is still less than 3.2

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22. After paying $7.50 for a movie ticket, Salvador still had $3.75. How much money did
Genrish500 [490]

Answer: $11.25

Step-by-step explanation:

Just add how much he spent ($7.50) and how much he had left ($3.75).

6 0
3 years ago
Write and equation for the following description:
Taya2010 [7]
I'm sorry I don't know
8 0
3 years ago
Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with μ=10
Tju [1.3M]

Answer: 0.8238

Step-by-step explanation:

Given : Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with \mu=106 and \sigma=15.

Let x denotes the scores on a certain intelligence test for children between ages 13 and 15 years.

Then, the proportion of children aged 13 to 15 years old have scores on this test above 92 will be :-

P(x>92)=1-P(x\leq92)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{92-106}{15})\\\\=1-P(z\leq })\\\\=1-P(z\leq-0.93)=1-(1-P(z\leq0.93))\ \ [\because\ P(Z\leq -z)=1-P(Z\leq z)]\\\\=P(z\leq0.93)=0.8238\ \ [\text{By using z-value table.}]

Hence, the proportion of children aged 13 to 15 years old have scores on this test above 92 = 0.8238

4 0
3 years ago
What is 400 in expanded form (Warfare you get brainliest)
MAXImum [283]
Hey there, Lets solve your question together 

Question - <span>What is 400 in Expanded form ? 
</span>
We know that expanded form is a spread out way to write a number by showing the value of each individual digit that contributes<span> to make the full number. 
</span>
Lets use an example to show expanded form

Number - 4,265 

= 4 x 1,000 + 2 x 100 + 6 x 10 + 5 x 1 

Now lets solve for the number 400 in expanded form. 

The number "4" is in the hundreds place 

The number "0" is in the tenths<span> place 
</span>
<span>The number "0" is in the One's place 

</span>Therefore 400 in expanded form is 400+00+0. 
 
<span>          Hope this helps </span>




5 0
3 years ago
Read 2 more answers
Each flower has a specific price. One tulip, one daisy, and 2 mums cost $4.20. On tulip, two daisies and one mum cost $3.80. Two
sineoko [7]

Answer:

The answer to your question is $5.60

Step-by-step explanation:

    1 tulip + 1 daisy + 2 mums = $4.20           (1)

    1 tulip + 2 daisies + 1 mum = $ 3.80         (2)

    2 tulips + 2 mums = $4.80                        (3)

    1 tulip + 3 daisies + 2 mums = ?

tulip = t      daisy = d      mum = m

Process

1.- Find the price of each flower using system of equations

    Solve equation 3 for tulip

     2t = 4.80 - 2 m     divide by 2                            (4)

     t = 2.40 - 1m

2.- Substitute equation 4 in equation 1 and 2

    (2.4 - 1m) + 1 d + 2 m = 4.2

    (2.4 - 1m) + 2d + 1 m = 3.8

3.- Simplify and solve for each flower

     2.4 - 1m + 1d + 2m = 4.2

      1d + 1m = 4.2 - 2.4

      1d + 1m = 1.8                   Equation (5)

     2.4 - 1m + 2d + 1m = 3.8

     2d = 3.8 - 2.4

     2d = 1.4

     d = 1.4/2

     1d = 0.7

4.-  Substitue d in equation 5

     1(0.7) + 1m = 1.8

     0.7 + 1m = 1.8

     1m = 1.8 - 0.7

      1m = 1.1

5.- Subtitute m in equation 4

     1t = 2.40 - 1(1.1)

     1t = 2.40 - 1.1

      1t = 1.3

6.- Result

     1 tulip + 3 daisies + 2 mums cost = 1.3 + 3(0.7) + 2(1.1)

                                                            = 1.3 + 2.1 + 2.2

                                                            = $5.6

8 0
3 years ago
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