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Luba_88 [7]
3 years ago
5

I’m new and I need help with this question.

Mathematics
1 answer:
Over [174]3 years ago
4 0

Answer:

First answer (question 7) -18 (question 8) -13 (question 9) -3 (question 10) -2

Step-by-step explanation:

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motikmotik
You most likely only need the first 3 digits after the decimal point but if you needed more i added them! hope this helps

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3 years ago
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Step-by-step explanation:

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3 years ago
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If P and Q are two sets then n( P-Q) means ?
Lapatulllka [165]

\huge{\mathbb{ \tt{ANSWER}}}

I shall use the symbol U for union

^ for intersection

~ for complement

<h3 /><h3>----------------------------------------------------------------------------------------------------</h3>

The property of set subtraction states that for any sets X and Y, X-Y = X ^ Y~

That is in words, X throw away Y is the same as the intersection of X and the complement of Y

or X and anything NOT in Y

At the SET level, the proof looks like this:

(P-Q) U (Q-P) = « given

(P^Q~) U (Q ^ P~) = « property of set subtraction

(P U Q) ^ (P U P~) ^ (Q~ U Q) ^ (Q~ U P~) = « distributive property

(P u Q) ^ (Q~ U P~) = « Union of any set with it's complement is the universal

set which gets dropped by any intersection of a non-universal set

(P u Q ) ^ (Q ^ P)~ = « De Morgan's Law

(P u Q) - (Q ^ P) = « property of set subtraction

(P u Q) - (P ^ Q) « commutative property

<h3>----------------------------------------------------------------------------------------------------</h3>

At the ELEMENT level, the proof looks like this:

» Proves left side is subset of right side

If x is in (P-Q) U (Q-P) then x is in (P-Q) OR x is in (Q-P)

If x is in P-Q then x is in P but not in Q.

Then X is in P U Q.

Since x is not in Q, x is NOT in P ^ Q

Hence x is in P U Q but NOT in P^Q, which

means it is an element if (P U Q) - (P ^ Q)

Therefore x is an element of the set defined by the right side, which means (P-Q) U (Q-P) is a subset of (P U Q) - (P ^ Q)

« proves right side is subset of the left side

If x is an element of (P U Q) - (P ^ Q) then

x is in (P U Q) but NOT in (P^Q)

Since x is in P U Q, x is in P OR x is in Q.

Since x is NOT in (P^Q) then x is NOT in BOTH P and Q.

Hence x is in either P or Q but not both.

If x is in P, then x is not in Q, so x is in P-Q.

Therefore x is in (P-Q) U (Q-P).if x is in Q, then x is not in P, so x is in Q-P.Therefore x is in (Q-P) U (P-Q).There x is an element of set defined by the left side, which menas (P u Q)-(P ^Q) is a subset of (P-Q) U (Q-P).

#CarryOnLearning

#LetsEnjoyTheSummer

<h3><u>»<em>X</em><em> </em></u><em><u>x</u></em><em><u> </u></em><em><u>K</u></em><em><u> </u></em><em><u>i</u></em><em><u> </u></em><em><u>m</u></em><em><u> </u></em><em><u>0</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>X</u></em></h3>
8 0
3 years ago
Many states run lotteries to raise money. A website advertises that it knows​ "how to increase YOUR chances of Winning the​ Lott
Crank

Complete question is;

Many states run lotteries to raise money. A website advertises that it knows "how to increase YOUR chances of Winning the Lottery." They offer several systems and criticize others as foolish. One system is called Lucky Numbers. People who play the Lucky Numbers system just pick a "lucky" number to play, but maybe some numbers are luckier than others. Let's use a simulation to see how well this system works. To make the situation manageable, simulate a simple lottery in which a single digit from 0 to 9 is selected as the winning number. Any value can be​ picked, but for this​ exercise, pick 1 as the lucky number. What proportion of the time do you​ win?

Answer:

10%

Step-by-step explanation:

We are told that To make the situation manageable, simulate a simple lottery in which a single digit from 0 to 9 is selected as the winning number.

This means the total number of single digits that could possibly be a winning one is 10.

Since we are told that only 1 can be picked, thus;

Probability of winning is; 1/10 = 0.1 or 10%

5 0
4 years ago
A trapezoid has the following dimensions:
mestny [16]
Area =
sum of the length of the parallel sides
multiplied by the distance between them
divided by two


area = \frac{(3+5) times by 3 }{2}

area = \frac{8 times by 3}{2}

area = \frac{24}{2}

area = 12

add the units:

area = 12 inches^{2}
4 0
3 years ago
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