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Orlov [11]
3 years ago
15

Divide 240 in the ratio 3:5.​

Mathematics
2 answers:
OLga [1]3 years ago
8 0

Answer:

90

Step-by-step explanation:

Arturiano [62]3 years ago
7 0

Answer: 3:5

Step-by-step explanation:let the ratios are 3x and 5x

therefore,3x+5x=240

8x=240

x=30

so,3x=3×30=90

5x=5×30=150

so,we divide 240 in 90 and 150 to get ratio 3:5

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On Sunday, Sheldon bought 4 1/2 kg of plant food. He used 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plant
VladimirAG [237]

Answer:

a) 2\frac{7}{12} kg of plant food did Sheldon have left.

b) She need is \frac{43}{12} kg and she don't have enough to left.

Step-by-step explanation:

Given : On Sunday, Sheldon bought 4\frac{1}{2} kg of plant food. He used 1\frac{2}{3} kg on his strawberry plants and used \frac{1}{4} kg for his tomato plants.

To find :

a) How many kilograms of plant food did Sheldon have left? Write one or more equations to show how you reached your answer.

Solution :

Sheldon bought plant food 4\frac{1}{2}=\frac{9}{2} kg.

He used strawberry plants 1\frac{2}{3}=\frac{5}{3} kg.

He used tomato plants \frac{1}{4} kg

Kilograms of plant food did Sheldon have left is given by,

L=\frac{9}{2}-(\frac{5}{3}+\frac{1}{4})

L=\frac{9}{2}-\frac{23}{12}

L=\frac{54-23}{12}

L=\frac{31}{12}

L=2\frac{7}{12}

Therefore, 2\frac{7}{12} kg of plant food did Sheldon have left.

b) Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will he need? Does he have enough left to do so?

Solution :

Sheldon wants to feed his strawberry plants 2 more times.

i.e. Strawberry plants used is 2(\frac{5}{3})=\frac{10}{3} kg.

His tomato plants one more time i.e. \frac{1}{4} kg.

Total plant she need is \frac{10}{3}+\frac{1}{4}=\frac{43}{12}

As \frac{31}{12}

No she don't have enough to left.

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3 years ago
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liq [111]

Answer:D and E are correect

Step-by-step explanation:

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Whitepunk [10]

Answer:

Step-by-step explanation:

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3 years ago
Two mechanics worked on a car. The first mechanic worked for 10 hours, and the second mechanic worked for 5 hours. Together they
inysia [295]
You have two unknown rates, so we need to develop two equations to solve for these unknowns (based on the information given on the problem statement):

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x + y = 100

By substitution, we get:

5x + 10(100 - x) = 725
5x + 1000 - 10x = 725
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x = -275/-5 = 55

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Thus:
The mechanic who worked for 5 hours charged his time at $55/hr, and the mechanic who worked for 10 hours charged his time at $45/hr.

To verify, plug and chug the results back into the original equations:

5(55) + 10(45) = 725
275 + 450 = 725
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55 + 45 = 100 [OK]
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timurjin [86]

Answer:

39

Step-by-step explanation:

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3 years ago
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