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3 years ago

11

Please help i am so confused

1 answer:

harkovskaia [24]3 years ago

3 0

Answer:

$q\geq -81$

Step-by-step explanation:

First, begin by multiplying $\frac{q}{27} \\$ by its reciprocal.

To do this, flip the fraction upside-down.

The resulting equation looks like this: $\frac{27}{1} *\frac{q}{27}$

Cancel out the two 27's and you are left with $\frac{q}{1}$ , which you can simplify to q.

Next, multiply -3 by $\frac{27}{1}$ . Remember, what you do on one side, you must do on the other.

Your equation should look like this:

$q\geq -81$

The final answer is $q\geq -81$ .

Have a nice day!

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3 years ago

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kati45 [8]

Answer:

$\frac{3b\sqrt[3]{c^{2}} }{a^{2} }$

Step-by-step explanation:

∛(27a⁻⁶b³c²)

To simplify, first apply the cube root the each of the terms. Keep in mind this rule: $\sqrt[n]{a^{m}} = (\sqrt[n]{a})^{m} = a^{m/n}$

∛27 = 3 (because 3*3*3 = 27)

∛a⁻⁶ = $a^{-6/3}$ = $a^{-2}$ = $\frac{1}{a^{2}}$

∛b³ = $b^{3/3}$ = $b^{1}$ = b

∛c² = $c^{2/3}$

∛(27a⁻⁶b³c²)

= $\frac{3b\sqrt[3]{c^{2}} }{a^{2} }$

Simplified form generally follows these rules:

No negative exponents

No fraction exponents

Keep in fractional form

Reduce numerical values

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3 years ago