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Artyom0805 [142]
3 years ago
12

Find the missing length of the right triangle.

Mathematics
1 answer:
Luden [163]3 years ago
3 0

Answer:

20...................

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Dmitri wants to cover the top and sides of the box shown with glass tiles that are 5mm square. How many tiles does he need? ( Th
ycow [4]

Answer:

372

Step-by-step explanation:

We are given that the dimensions of the box are,

Length = 15 cm, Width = 20 cm and Height = 9 cm.

We know that the box represents a cuboid.

Since, surface area of a cuboid = L×W + 2×L×H + 2×W×H

Thus, the surface area of the box = 15×20 + 2×15×9 + 2×20×9

i.e. Surface area = 300 + 270 + 360

i.e. Surface area = 930.

Thus, the surface area of the box is 930 cm² i.e. 9300 mm².

Further, the sides of the tiles are 5 mm and the tile represents a square.

So, the surface area of the tile = 5 × 5 = 25 mm².

This gives us that,

Number of tiles required to cover the box = \frac{9300}{25} = 372.

Hence, Dmitri requires 372 tiles to cover the box.

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3 years ago
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il63 [147K]

Answer:

here the link:

78siga6q9mm

8 0
3 years ago
Which list shows the runners in order by their completion times from fastest to slowest
gogolik [260]

Answer:

answer is D

Step-by-step explanation:

12+1/2=12.5          12+2/5=12.4

3 0
3 years ago
What is y in the equation 14-6y=44
Ostrovityanka [42]
14-6y=44
-14 Both sides
-6y=30
÷-6 both sides
Y=-5
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3 years ago
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There are 7800 grams of lodine that have a half-life of 8 days. How much lodine will remain after 40 days?
anygoal [31]

Given that we know the initial mass of Iodine and its half-life, we want to see how much will remain after 40 days.

After 40 days, 244.17 grams of Iodine will remain.

<h3 /><h3>The half-life of materials and how to use it:</h3>

The half-life of a material is the time it takes for that amount of material to reduce to its half.

We can model the amount of Iodine as:

A(t) = A*e^{k*t}

  • Where A is the initial amount, in this case, 7800g.
  • k is a constant that depends on the half-life.
  • t is the time in days.

Replacing what we know, we get:

A(t) = 7800g*e^{k*t}

Now we use the fact that the half-life is 8 days, this means that:

e^{k*8} = 1/2

ln(e^{k*8}) = ln(1/2)

k*8 = ln(1/2)

k = ln(1/2)/8 = -0.0866

Then the function is:

A(t) =  7800g*e^{-0.0866*t}

So now we just need to evaluate this in t = 40.

A(40) = 7800g*e^{-0.0866*40} = 244.17g

So, after 40 days, 244.17 grams of Iodine will remain.

If you want to learn more about half-life and decays, you can read:

brainly.com/question/11152793

3 0
2 years ago
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