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mote1985 [20]
3 years ago
14

The function f(x)=logx is transformed into the equation f(x)=log(1/4x).

Mathematics
1 answer:
lesya692 [45]3 years ago
8 0

Answer:

Given the parent function: f(x) =\log x

Rule for Horizontal Stretches and Compression:

If parent function y=f(x), then y=f(cx) gives a horizontal stretch when  c >1 and

a horizontal compression when 0<c<1.


therefore, by above definition

the function f(x) = \log(\frac{1}{4}x) is a Horizontal compression by a factor of c =\frac{1}{4} = 0.25

therefore, the function  f(x) = \log(\frac{1}{4}x) is HORIZONTAL COMPRESSION of the parent function by a factor of 0.25

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Answer:

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, a=-b

Step-by-step explanation:

The domain refers to values for which the expression is defined.

This implies that, the denominators are not equal to zero.

(\frac{a + b}{b} -  \frac{a}{a + b}) \div ( \frac{a + b}{a} -  \frac{b}{a + b})

(\frac{(a + b)(a + b)-ab}{b(a + b)})\div(\frac{(a + b)(a + b)-ab}{a(a + b)})

\frac{(a + b)(a + b)-ab}{b(a + b)} \times\frac{a(a + b)}{(a + b)(a + b)-ab}

\implies \frac{a}{b}

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, and a=-b

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3 years ago
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Absolute value inequality<br>4 |x+7| divided by 3. ?
stira [4]

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3 years ago
Question. 1 :
vovikov84 [41]
<h3>Answer to Question 1:</h3>

AB= 24cm

BC = 7cm

<B = 90°

AC = ?

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

AC^2 = 24^2 + 7^2

AC^2 = 576 + 49

AC^2 = √625

AC = 25

<h3>Answer to Question 2 :-</h3>

sin A = 3/4

CosA = ?

TanA = ?

<h3>SinA = Opp. side/Hypotenuse</h3><h3> = 3/4</h3>

(Construct a triangle right angled at B with one side BC of 3cm and hypotenuse AC of 4cm.)

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

4² = AB² + 3²

16 = AB + 9

AB = √7cm

<h3>CosA = Adjacent side/Hypotenuse</h3>

= AB/AC

= √7/4

<h3>TanA= Opp. side/Adjacent side</h3>

=BC/AB

= 3/√7

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2 years ago
Choose Yes or No to tell if each statement is true.
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not 100% sure

hope it helped

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