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pychu [463]
2 years ago
12

A developer bought 78 trees at a total cost of $4050. The shade trees cost $45 each and the evergreens cost $60 each. How many o

f each type of tree were bought?
Mathematics
1 answer:
ANTONII [103]2 years ago
6 0

Answer:

Step-by-step explanation:

for 5 feet is $60

2 feet is $150.

sorry if this doesn't help!

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Please help out with this if you can.
Pepsi [2]

Answer:

3/7 and 4/17

Step-by-step explanation:

a) given that Shen is playing a game and the probability of unlocking the treasure test is 3/10.

To find the odds in favour of his character unlocking the treasure chest.

Since probability = 3/10 we have favourable and total are in the ratio 3:10

i.e. favourable:Favourable+unfavourable= 3:3+7

Hene odds= favourable:unfavourable =3/7

Answer is 3/7

b) Given that odds against choosing a blue block are 13/4

This means there are 4 blue blocks and 13 other colour blocks.

Total blocks= 13+4 =17

No of blue blocks = 4

Probability of selecting blue block=4/17


6 0
3 years ago
Can someone explain what these types of arrows mean please?
Yakvenalex [24]
I think it means grater or less ? Or positive or negative?
8 0
2 years ago
Solve 2x + 4 &gt; 16.<br> NEED ANSWER ASAP
antiseptic1488 [7]

Answer:

x>6

Step-by-step explanation:

2x > 16-4

x > 12/2

x > 6

7 0
2 years ago
Read 2 more answers
three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

=     3x + \frac{6}{5} = \frac{27}{4}

=     3x = \frac{27}{4} - \frac{6}{5}

( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

=     3x = \frac{111}{20}

=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

So, the weight of the equal bags are \frac{37}{20} and the weight of the third bag ( heavy one ) is \frac{37}{20} + \frac{6}{5} = \frac{37}{20} + \frac{24}{20} = \frac{61}{20}

1st bag =     \frac{37}{20} kg

2nd bag =  \frac{37}{20} kg

3rd bag =   \frac{61}{20} kg

Hope it helps...

7 0
3 years ago
3. Describe the solution to the equation.
Law Incorporation [45]
I don’t really know? What grade is this?
4 0
3 years ago
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