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2 years ago

The figure shows a large triangle divided into two smaller triangles what is the value of x in the figure

Mathematics

1 answer:

nata0808 [166]2 years ago

6 0

Answer:

Step-by-step explanation:

Find the other missing angle, which is supplementary to 100 first.

Supplementary angels are a sum of 180

The missing angle is 180-100 = 80

Now use that to find missing angle x

All angles in the triangle have a sum of 180

180 = 60+80+x

180-60-80=x

40 = x

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The area of a room is 600 square feet. The length is (x+2) feet and the width is (x+3) feet. Find the dimensions of the room

m_a_m_a [10]

Create an equation using the formula for area of a rectangle; area = width * length
(X + 2)(x + 3) = 600
Multiply the dimensions.
X^2 + 3x + 2x +6 = 600, or simplified x^2 +5x + 6 = 600.
Subtract 600 to get the following:
X^2 + 5x - 594 = 0
Factor by x:
(X - 22)(x + 27) = 0
Solve for x
X - 22 = 0
X = 22.
Use the POSITIVE VALUE of x as you can’t have a negative area for a room.
Then substitute 22 for x to get the dimensions
(22+ 2) or 24 for length and (22+3) or 25 for width.

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2 years ago

What is the measure of

Alona [7]

Yeh provide more info

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2 years ago

What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$