Number 1 might be A and number 2 might be B. I'm not sure though.
A(n) = 2 + 9(n - 1) = 2 + 9n - 9
A(n + 1) = 2 + 9(n + 1 - 1) = 2 + 9n = (2 + 9n - 9) + 9 = A(n) + 9
Therefore, the recursive formular is A(n) = A(n - 1) + 9
Step-by-step explanation:
1st) Distribute 8 with x and 8 with -1 which will give you
8x-8=5x-35
2nd) Use opposite operation and add 8 both sides
8x-8=5x-35
+8 +8
---------------
8x=5x-27
3rd) subtract 5x from both sides
8x=5x-27
-5x= -5x
_______
3x=-27
4th) Divide 3 from both sides so -27 by 3
3x=-27
_ _
3 3
ANSWER X=-9
4x + 5y = 2(x + 3y)
4x + 5y = 2x + 6y <em>distributed 2 on the right side</em>
2x + 5y = 6y <em>subtracted 2x from both sides</em>
2x = y <em>subtracted 5y from both sides</em>
if y = 2x
then 17(y) = 17(2x)
17y = 34x
Answer: 34x