We are given a problem that can be solved using a system of linear equations. Let A, be the number of adults, and S the number of students. Since there are in total 142 people and there were two days, this means that the sum of the number of adults and the number of students must be 284, which can be written mathematically as follows:

This is our first equation. The second equation is found using the total sales of $1948. Since the ticket per adult is $8 and per student is $5, we have the following equations:

To solve this equation we will solve for A in equation (1), by subtracting S to both sides;

Now we will replace this value in equation (2):

Now we will apply the distributive property:

Addins like terms:

Subtracting 2272 to both sides;

Dividing both sides by -3:

Now we replace this value in equation (1), where we have already solved for A:

Therefore, there were sold 108 student tickets and 140 adult tickets.
C. There were 5 footballs sold for every 2 basketballs. to check just multiply 2 times 2.5 and you get 5. Hope this helped
A = 1
b = -2
c = -3
And when you plug in and solve you'll get correct answers of x = 3 and x = -1
The first penalty they received is three 15 yards so total yards is 3(15 yards)
the second penalty is one 5 yard
the last penalty is half the 34 yard line(34 yard)/2
total change = 3(15 yards) + 5 yrad + (34 yard)/2
= 45 yards + 5 yards + 17 yards= 67yards