Answer:
We can conclude that there is significant evidence that dL fertilizer has a positive impact on larger weight of coms
Step-by-step explanation:
Given the data :
8.25 7.35 9.05 8.00 8.25 8.75 9.00 7.60 8.45 8.55
Using calculator :
Mean, x = 8.325
Standard deviation, s = 0.560
Null hypothesis :
H0: μ = 8
H1 : μ > 8
The test statistic,
(x - μ) / (s/sqrt(n))
(8.325 - 8) / (0.56 / sqrt(10))
0.325 / 0.177
= 1.835
The Pvalue ; using the Tstatistic calculator ;
α = 0.05 ; df = 10 - 1 = 9
Pvalue = 0.04985
Reject H0 ; if Pvalue is < α
Hence, since 0.04985 < 0.05 ; we reject H0
. We can conclude that there is significant evidence that dL fertilizer has a positive impact on larger weight of coms
Answer:
b
Step-by-step explanation:
Answer:
200 miles
Step-by-step explanation:
First, set up the equations.
plan 1: initial fee of $55.96, $0.12 per mile
plan 2: initial fee of $63.96, $0.08 per mile
We want to know at what distance will the cost be the same. So, set the equations equal to each other.
0.12x + 55.96 = 0.08x + 63.96
Combine the variables.
0.04x + 55.96 = 63.96
Combine the constants.
0.04x = 8
Divide by 0.04 to isolate x.
x = 200 miles
Check by plugging x back into each equation.
y = 0.12(200) + 55.96
y = 24 + 55.96
y = $79.96
y = 0.08(200) + 63.96
y = 16 + 63.96
y = $79.96
You are correct!
