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user100 [1]
3 years ago
14

The equivalent expression for 16x + 46 + 8c

Mathematics
1 answer:
pickupchik [31]3 years ago
7 0

Answer:

=8c+16x+46

Step-by-step explanation:

you just switch around the equation

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The number of students enrolled at a college is 15,000 and grows 4% each year
Kipish [7]

Answer:

15,000

Step-by-step explanation:

initial amount is basically the starting amount

6 0
3 years ago
Which of these number is irrational?<br><br> a) 9.6<br> b) √45 <br> c) 3/8<br> d) 3.4 x 10 ⁵
bearhunter [10]

Answer:

I think (D)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Prove the divisibility of the following numbers:
Brut [27]

Answer:

Step-by-step explanation:

To prove divisibility, we need to factor the divident such that one of its factors matches the divisor.

(I use the notation x|y to denote that x divides y)

(A)

75^{30}|45^{45}\cdot15^{15}\\45^{45}\cdot15^{15}=3^{45}\cdot 15^{45}\cdot 15^{15}=\\=3^{45}\cdot 15^{60}=3^{45}\cdot 15^{30}\cdot 15^{30}=3^{45}\cdot (3\cdot5)^{30}\cdot 15^{30}=\\=3^{45}\cdot 3^{30}\cdot(5\cdot 15)^{30}=3^{45}\cdot 3^{30}\cdot(75)^{30}\\\implies\\75^{30}|3^{45}\cdot 3^{30}\cdot75^{30}

(B)

72^{63}|24^{54}\cdot 54^{24}\cdot2^{10}\\24^{54}\cdot 54^{24}\cdot2^{10}=(2^{162}\cdot 3^{54})\cdot(2^{24}\cdot 3^{72}) \cdot 2^{10}\\=2^{196}\cdot 3^{126}

In this case, it is easier to also factor the divisor to primes:

72^{63}=2^{189}\cdot 3^{126}

Both of these factor must be matched in the dividend in order to prove divisibility, and that indeed turns out to be true:

2^{189}\cdot 3^{126}|2^{196}\cdot 3^{126}\implies\\2^{189}|2^{196}\,\,\mbox{and}\,\,3^{126}|3^{126}

6 0
3 years ago
A tiger weighs 617 pounds.<br> Another tiger weighs 326 pounds.<br> How much do they weigh total?
irina [24]
943 pounds when you add them together
5 0
3 years ago
Evaluate m = for for m = 1 and (x1, y1) = (0, 2) and (x2, y2) = (x, 0).
77julia77 [94]
We know that
the slope formula is
m=(y2-y1)/(x2-x1)
(x1,y1)=(0,2)
(x2,y2)=(x,0)
m=1-----> equation 1
m=(0-2)/(x-0)------> m=-2/x -----> equation 2

equate equation 1 and equation 2
1=-2/x------> multiply by x both sides------> x=-2

the point (x2,y2) is ----------> (-2,0)
3 0
3 years ago
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