Given:
p = 20% = 0.2, sample proportion
n = 5000, sample size.
Confidence level = 95%
The confidence interval is
(p - 1.96k, p + 1.96k)
where

Therefore the 95% confidence interval is
(0.1943, 0.2057) = (19.4%, 20.6%)
Answer: The 95% confidence interval is (19.4%, 20.6%)
Answer:
B
Step-by-step explanation:
Answer:
Step-by-step explanation:
N = 3rt^4 - 5rz
now factor r out
N = r(3t^4-5z)
divide by r on both sides
N/r = (3t^4 - 5z)
subtract (3t^4)
N/r - 3t^4 = -5z
now divide by -5 to isolate the variable (z)
= z
Answer:
10
Step-by-step explanation:
m = least prime number = 2
n = least positive integer multiple of 12 = 12
n - m = 12 - 2 = 10
Answer:
9(6+3) = 54+27
Step-by-step explanation:
dunno how to explain but hope the answer helps