All categories

2 years ago

What are the possible numbers of positive, negative, and complex zeros of f(x)=-3x^4+5x^3-x^2+8x+4

Mathematics

1 answer:

Andru [333]2 years ago

7 0

Answer:

There could be 0, 2, or 4 complex solutions

Step-by-step explanation:

The Fundamental Theorem of Algebra states that any polynomial with n degree will have n solutions So since the degree of the polynomial you provided has a degree of 4, that means there are 4 possible solutions. This question specifically asks for complex zeroes. Complex zeroes come in conjugate pairs, so that means if you have one complex zero, there is another complex zero which is it's conjugate. For this reason, there can only be an even number of complex zeroes. And since there's 4 possible solutions, There could be 0, 2, or 4 complex solutions

You might be interested in

First right gets brainliest:)

Jet001 [13]

First equation: x=-y+8
Second equation: on the picture

4 0

3 years ago

If (angle)1 = 7x and (angle)4 = 3x + 20, what is the value of x?

Semenov [28]

The value of x is 5. Angle one and four are vertical. You can do this by writing 7x = 3x + 20. Isolate the variable by moving 3x to the other side. If you do this, 3x becomes negative, and you end up with 7x-3x = 20 --> 4x = 20.
x=5.

7 0

3 years ago

Read 2 more answers

I need help please!!!

e-lub [12.9K]

There is no distinct pattern, the scatter plot would be up down and spread apart, nothing really correlated.

3 0

2 years ago

Prove the trigonometric identity

Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

$1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1$

Lets solve the bottom most part first:

$1-\frac{1}{1-sec^2x} \\\\$

Take LCM

$1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}$

now break the LCM

$\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1$

because 1/tan = cot x

and furthermore,

$cot^2x+1\\cosec^2x$

now we solve the above part and replace the bottom most part that we solved with $cosec^2x$

$\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x$

Hence proved! :D

4 0

3 years ago

How do I convert 216 in percentage

AveGali [126]

Answer: 21600

216 as a percentage of certain number x can be calculated by dividing 216 by x, and multiplying the result by 100. For example, 216 as a percentage of 10 = (216 / 10) x 100% = 2160%.

Step-by-step explanation:

6 0

2 years ago