The required probability of the coin landing tails up at least two times is 15/16.
Given that,
A fair coin is flipped seven times. what is the probability of the coin landing tails up at least two times is to be determined.
<h3>What is probability?</h3>
Probability can be defined as the ratio of favorable outcomes to the total number of events.
Here,
In the given question,
let's approach inverse operation,
The probability of all tails = 1 / 2^7 because there is only one way to flip these coins and get no heads.
The probability of getting 1 head = 7 /2^7
Adding both the probability = 8 / 2^7
Probability of the coin landing tails up at least two times = 1 - 8/2^7
= 1 - 8 / 128
= 120 / 128
= 15 / 16
Thus, the required probability of the coin landing tails up at least two times is 15/16.
Learn more about probability here:
brainly.com/question/14290572
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Answer:
APEX x=-3
Step-by-step explanation:
x+3=0->x=-3
Step-by-step explanation:
<B is the right angle
<A is acute
<C is acute
<D is obtuse
Answer:
see below
Step-by-step explanation:
dx 2+2xy 1 1 2 2
____ = ______ – ___x^2 – ____y^2 – _____x + ______y
dy 3 3 3 3 3
Answer:
Dear student,
Answer to your query is provided below
Probability of drawing a 2 at first is (4/52) = (1/13)
Probability of drawing a face card in second try without replacement = 12/51
Step-by-step explanation:
Total no. Of cards = 52
Total no. Of cards of 2 = 4
Prob. Of drawing 2 = 4/52
Total no. Of face card = 12
Total no.of cards left in deck = 51
Prob. Of drawing face card = 12/51
