Answer:
A. BC ≈ 2.52; AB ≈ 1.28; m∠C = 27°
B. BC ≈ 1.28; AB ≈ 2.52; m∠C = 27°
C. BC ≈ 2.52; AB ≈ 1.28; m∠C = 117°
D. BC ≈ 1.28; AB ≈ 2.52; m∠C = 117°
Calculate the z-score for the given data points in the item using the equation,
z-score = (x - μ) / σ
where x is the data point, μ is the mean, and σ is the standard deviation.
Substituting,
(47.7) z-score = (47.7 - 52.5)/2.4 = -2
This translates to a percentile of 2.28%.
(54.9) z-score = (54.9 - 52.5)/2.4 = 1
This translates to a percentile of 84.13%.
Then, subtract the calculate percentiles to give us the final answer of <em>81.85%.</em>
Thus, 81.85% of the Siberian Husky sled dogs are expected to weigh between 47.7 and 54.9 lbs.
Answer:
Question 1: Option C, 2x^2(x - 3)(x^2 + 3x + 9)
Question 2: Options 1, 2, 5
Step-by-step explanation:
Question #3
Step 1: Factor
2x^5 − 54x^2
2x^2(x^3 - 27)
<em>2x^2(x - 3)(x^2 + 3x + 9)</em>
<em />
Answer: Option C, 2x^2(x - 3)(x^2 + 3x + 9)
Question #2
p(x) = 4x^6 + 32x^3
<u>Step 1: Factor</u>
4x^6 + 32x^3
4x^3(x^3 + 8)
<em>4x^3(x + 2)(x^2 - 2x + 4)</em>
<em />
Answer: Options 1, 2, 5
