Answer:
The y-intercept is the point (0,-8)
see the attached figure
Step-by-step explanation:
we have
we know that
The y-intercept is the value of the function f(x) when the value of x is equal to zero
so
For x=0
therefore
The y-intercept is the point (0,-8)
see the attached figure to better understand the problem
D) these two figures are similar they don't look similar at first because the X'Z'Y' is more upwards. But they are congruent meaning they are similar or exactly the same almost. This basically tells me that I need to use translation.
E) I can use reflection to get XYZ into X'Y'Z' by reflecting it across the x-axis. I could also use translation and move it up 6 and then move it to the right.
C) The last one I could use is rotation and move it around around 45* or something close to the the other one.
Question: When is this due?
You will factor out the common factor of t if you are solving for t. you will then divide both sides by (s+3) to make t the subject of the formula. for this question you can only get t in terms of s.
so:
st+3t=6
t(s+3)/(s+3)=6/(s+3)
t=6/(s+3)
if you are required to solve for s then you are going to subtract 3t from both sides. you can factorise 6-3t .you will then divide both sides by t to isolate s.for this question you can only get s in terms of t.so:
st+3t-3t=6-3t
st/t=2(3-t)/t
s=2(3-t)/t
Answer: OPTION A.
Step-by-step explanation:
Given the following function:
You know that it represents the the height of the ball (in meters) when it is a distance "x" meters away from Rowan.
Since it is a Quadratic function its graph is parabola.
So, the maximum point of the graph modeling the height of the ball is the Vertex of the parabola.
You can find the x-coordinate of the Vertex with this formula:
In this case:
Then, substituting values, you get:
Finally, substitute the value of "x" into the function in order to get the y-coordinate of the Vertex:
Therefore, you can conclude that:
<em> The maximum height of the ball is 0.75 of a meter, which occurs when it is approximately 1 meter away from Rowan.</em>