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garik1379 [7]
2 years ago
8

HELP ME OUT PLSSS ALSO DUE TODAY!

Mathematics
2 answers:
stepladder [879]2 years ago
7 0
Answer x > -15
explanation
disa [49]2 years ago
4 0

Answer:

x > -15, you are welcome we all need help

You might be interested in
Randy filled 48 pint jars to the top with jelly. How many gallons of jelly did Randy make it? Explain.
cestrela7 [59]

Answer:

24

Step-by-step explanation:

The conversion is half (1/2) Every 1 quart is two pints. If Randy had 48 pints of jelly, we simply divide 48 by 2...


48/2=24

3 0
3 years ago
How much, in total, did Noel spend to cash her three most recent paychecks?
Stolb23 [73]

Based on the amount that Noel cashed in each of her most recent paychecks, the amount she spent in total is $10.99.

<h3>How much did Noel spend?</h3>

The bank directory shows that you are charged 1.99% of the amount being cashed as well as a check processing fee of $1.39.

The amount Noel spent is therefore:

= (1.99% x 100.53) + (1.99% x 119.38) + (1.99% x 122.52) + (1.39 x 3 checks)

= 2.00 + 2.38 + 2.44 + 4.17

= $10.99

Find out more on bank charges at brainly.com/question/26494219.

3 0
2 years ago
Simplify
Klio2033 [76]

Answer:

10x-2y

Step-by-step explanation:

distribute for both of them then multiply both answers by 2 and add them

2(x+y)= (2x+2y) x2= 4x+4y

3(x-y)= (3x-3y) x2= 6x-6y

4x+4y+6x-6x

10x-2y

5 0
3 years ago
What is the value of m in the equation 1/2 m - 3/4 n = 16, when n=8? <br>20 <br>32 <br>44 <br>48​
olasank [31]

Answer:

48 567i900yhhf free in nkko of h

7 0
3 years ago
Read 2 more answers
A country's population in 1993 was 127 million. In 2000 it was 132 million. Estimate the population in 2008 using the exponentia
12345 [234]
To solve the exponential growth application question we proceed as follows;
suppose the time, t between 1993 to 2000 is such that in 1993, t=0 and in 2000, t=7.
Note theta the population is in millions;
The exponential formula is given by:
f(t)=ae^(kt)
where;
f(t) =current value
a=initial value
k=constant of proportionality
t=time
substituting the values we have in our formula we get:
132=127e^(7k)
132/127=e^(7k)
introducing the natural logs we get:
ln (132/127)=7k
k=[ln(132/127)]/7
k=0.0055
Thus our formula will be:
f(t)=127e^(0.0055t)
The population in 2008 will be:
f(t)=127e^(15*0.0055)=127e^(0.0825)=137.922
Thus the population in 2008 is appropriately 138 million.

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5 0
4 years ago
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