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Lostsunrise [7]
3 years ago
9

5*Please answer this correctly very urgent!

Mathematics
2 answers:
Vanyuwa [196]3 years ago
8 0

Answer:

1  3/15 - 5/15

Step-by-step explanation:

Hope this helps. PS the / sign is supposed to be for the fraction.

Komok [63]3 years ago
5 0

Step-by-step explanation:

1 1/5 - 1/3 = 0.86

Hope I helped. The only way I know how to dot this is in decimal form sorry.

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What is 2 2/5×2 7/9 in simplest mixed number form?
Scorpion4ik [409]

Answer:

6 2/3

Step-by-step explanation:

2 2/5 * 2 7/9

Change each number to an improper fraction

2 2/5 = (5*2+2)/5 = 12/5

2 7/9 = (9*2+7) = 25/9

12/5 * 25/9

Rewriting

25/5  * 12/9

5/1 * 4/3

20/3

Now changing to a mixed number

3 goes into 20 6 times with 2 left over

6 2/3

7 0
3 years ago
Which of the following is a arithmetic sequence?
Vesnalui [34]

Answer:

What are the options

Step-by-step explanation:

6 0
3 years ago
true or false Microwave ovens cause friction between water molecules, which then generates chemical energy to cook your food.
den301095 [7]
That is true that microwave ovens cause friction to water molecules
8 0
3 years ago
Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0
3 years ago
The mean game scores and standard deviations of four seasons of a football team are given below. Season Mean Standard Deviation
timurjin [86]
To find the margin of error, multiply the z-score by the standard deviation, then divide by the square root of the sample size.The z*-score for a 90% confidence level is 1.645.The margin of error is 0.20.The confidence interval is 48.3 to 48.7.48.8 is not within the confidence interval. 
7 0
3 years ago
Read 2 more answers
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