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3 years ago

PLEASE HELP ME FOR EXTRA POINTS AND BRAINLIEST ANWSER

Mathematics

2 answers:

dedylja [7]3 years ago

6 0

The answer is 45 degrees.

MatroZZZ [7]3 years ago

3 0

The answer is 45 degrees

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Find x if AB = 9, BC = 2x - 5,<br> and AC = x + 9

Oxana [17]

Answer:

x = 5

Step-by-step explanation:

Using the fact that line segments AB and BC are parts of the whole line segment AC, we can write the following equation:

AB + BC = AC

Now, using the given values, we can substitute in for the equation and solve for x:

AB + BC = AC

9 + 2x - 5 = x + 9

2x + 4 = x + 9

x = 5

Thus, we have found that for these sets of equations for these line segments, our value for x should be 5.

Cheers.

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3 years ago

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What is 34 divided by the square root of 5

Margaret [11]

Answer:

15.205

Step-by-step explanation:

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3 years ago

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find the measure of the angle of elevation of the sun to the nearest degree, if a 100ft tall building casts a 150ft shadow.

Svet_ta [14]

Answer:

33.7º

Step-by-step explanation:

tan = opp/adj

tan∅ = 100/150 = 2/3

∅ = arctan 2/3

∅ = 33.690067525979787

33.7º

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3 years ago

An individual who has automobile insurance from a certain company is randomly selected. Let y be the number of moving violations

Hoochie [10]

Answer:

a) $E(Y)= \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

$E(Y) = 0*0.45 +1*0.2 +2*0.3 +3*0.05= 0.95$

b) $E(80Y^2) =80[ 0^2*0.45 +1^2*0.2 +2^2*0.3 +3^2*0.05]= 148$

Step-by-step explanation:

Previous concepts

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).

And the standard deviation of a random variable X is just the square root of the variance.

Solution to the problem

Part a

We have the following distribution function:

Y 0 1 2 3

P(Y) 0.45 0.2 0.3 0.05

And we can calculate the expected value with the following formula:

$E(Y)= \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

$E(Y) = 0*0.45 +1*0.2 +2*0.3 +3*0.05= 0.95$

Part b

For this case the new expected value would be given by:

$E(80Y^2)= \sum_{i=1}^n 80Y^2_i P(Y_i)$

And replacing we got

$E(80Y^2) =80[ 0^2*0.45 +1^2*0.2 +2^2*0.3 +3^2*0.05]= 148$

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3 years ago

Ryan has a board that is 5 feet long. how many 1/3-foot sections can he cut from this board?

labwork [276]

Ryan can cut 15 pieces from the board

7 0

3 years ago