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Ksju [112]
2 years ago
8

Find the length of the third side.

Mathematics
1 answer:
Yanka [14]2 years ago
8 0

I'm not sure if I did this right.

Answer:

2

Step-by-step explanation:

1^2+x^2=\sqrt{5}^2

x^2+1=5

x=\frac{+}{-} \sqrt{4}

2 or -2

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Which of the following numbers is a multiple of 6? <br><br> A. 106<br> B. 333<br> C. 424<br> D. 882
brilliants [131]
882 is a multiple of 6. if you multiply 6 by 147, you get 882.
4 0
2 years ago
How many solutions does the equation 9x-3(x+8)=6x-24
Marina86 [1]
Simplifying
9x + -3(x + 8) = 6x + -24

Reorder the terms:
9x + -3(8 + x) = 6x + -24
9x + (8 * -3 + x * -3) = 6x + -24
9x + (-24 + -3x) = 6x + -24

Reorder the terms:
-24 + 9x + -3x = 6x + -24

Combine like terms: 9x + -3x = 6x
-24 + 6x = 6x + -24

Reorder the terms:
-24 + 6x = -24 + 6x

Add '24' to each side of the equation.
-24 + 24 + 6x = -24 + 24 + 6x

Combine like terms: -24 + 24 = 0
0 + 6x = -24 + 24 + 6x
6x = -24 + 24 + 6x

Combine like terms: -24 + 24 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0
7 0
3 years ago
Read 2 more answers
Segments
Kazeer [188]

Given

AB  and  CD  intersect

AC,  CB,  BD  and  AD  are congruent.

Prove that AB  is the bisector of ∠CAD and ray  CD  is the bisector of ∠ACB.

and AB  and  CD  are perpendicular.

To proof

Bisector

<em>A bisector is that which cut an angle in two equal parts.</em>

In ΔACB and ΔADB

AD = AC  ( Given )

AB = AB   ( common )

BC = DB  ( Given )

by SSS congurence property

we have

ΔACB ≅ΔADB

∠CAB =∠ DAB

∠CBA = ∠DBA

( By corresponding sides of the congurent triangle )

Thus AB is the bisector of the ∠CAD.

InΔ DAC and ΔDBC

AD = DB (Given)

AC = CB  ( Given )

CD = CD (common)

By SSS congurence property

ΔDAC≅ Δ DBC

∠  ACD =∠ BCD

∠ADC =∠BDC

( By corresponding sides of the congurent triangle )

Therefore CD is the bisector of the CAD.

In ΔBOC andΔ BOD

BO = BO ( Common )

∠BCO = ∠BDO

( As prove above ΔACB ≅ΔADB

Thus ∠ACB = ∠ADB by corresponding sides of the congurent triangle , CD is a bisector

∠BCO = ∠BDO )

 CB = DB ( given )

by SAS congurence property

ΔBOC ≅ ΔBOD

∠BOC =∠ BOD

∠BOC +∠ BOD = 180 °( Linear pair )

2∠ BOC = 180°

∠BOC = 90°

∠BOC =∠ BOD = 90°

also

In ΔCOA and ΔAOD

AO = AO ( Common )

∠ACO =∠ ADO

(  As prove above ΔACB ≅ΔADB Thus ACB = ADB by corresponding sides of congurent triangle ,CD is a bisector

thus  ∠ACO = ∠ADO )

AC =AD ( given )

by SAS congurence property

Δ COA ≅ ΔAOD

∠AOC = ∠AOD

( By corresponding angle of corresponding sides )

∠AOC + ∠AOD = 180°

2∠ AOC = 180°   ( Linear pair )

∠AOC = 90°

∠AOC = ∠AOD = 90 °

Thus AB  and  CD  are perpendicular.

Hence proved









   


 



6 0
3 years ago
Multi step equations​
baherus [9]

Answer:

what is the problem?

Step-by-step explanation:

3 0
3 years ago
WHAT IS "K" <br> 310 minus (30 times 7) = 5 times k
RSB [31]

Answer:

k = 20

Step-by-step explanation:

310-(30x7) = 5k

310-210=5k

100=5k

 /5   /5

20=k

7 0
3 years ago
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