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2 years ago

For questions 9 and 11, solve for the remaining angles.

Mathematics

1 answer:

maw [93]2 years ago

4 0

Answer:

‹A = 141°

‹B = 28°

‹C = 11°

*These angles are rounded to the nearest whole*

Step-by-step explanation:

Because you are only given sides you can find an individual angle measures with the inverse law of cosines.

Remember the side opposite of the angle corresponds to that angle.

a² = b² + c² - 2bc cos(A) →

A = cos⁻¹ (a² - b² - c² / -2bc)

b² = a² + c² - 2ac cos(B) →

B = cos⁻¹ (b² - a² - c² / -2ac)

c² = a² + b² - 2ab cos(C) →

C = cos⁻¹ (c² - a² - b² / -2ab)

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Explain how 2 plus 2 Equals 4

aivan3 [116]

You have 2+2 in each 2 there are 1's so

2=(1+1) 2=(1+1) =4
4=1+1+1+1
2+2=4
think of 2's as 1's when adding did you know 2x2= 4 as well.

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3 years ago

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Artist 52 [7]

Answer:

SOLUTION: X=5

Step-by-step explanation:

x=5

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Hope that helps!

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3 years ago

Find an antiderivative F(x) with F′(x) = f(x) = 6 + 24x^3 + 18x^5 and F(1)=0.

7nadin3 [17]

Answer:

The antiderivative is $F(X) = 6x + 6x^4 + 3x^6 - 15$ .

Step-by-step explanation:

Antiderivative F(x)

This is the integral of $F^{\prime}(x)$

F′(x) = f(x) = 6 + 24x^3 + 18x^5

Then:

$F(x) = \int (6 + 24x^3 + 18x^5) dx$

$F(x) = 6x + \frac{24x^4}{4} + \frac{18x^6}{6} + K$

$F(x) = 6x + 6x^4 + 3x^6 + K$

F(1)=0

$F(X) = 0$ when $x = 1$ . We use this to find K.

$F(x) = 6x + 6x^4 + 3x^6 + K$

$0 = 6 + 6 + 3 + K$

$K = -15$

Thus

The antiderivative is $F(X) = 6x + 6x^4 + 3x^6 - 15$ .

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3 years ago

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marusya05 [52]

Answer:

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3 years ago

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Mekhanik [1.2K]

Answer:

$0.33 or 33¢

Step-by-step explanation:

33/100 = 0.33 = $0.33

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3 years ago