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Bond [772]
2 years ago
14

For questions 9 and 11, solve for the remaining angles.

Mathematics
1 answer:
maw [93]2 years ago
4 0

Answer:

‹A = 141°

‹B = 28°

‹C = 11°

*These angles are rounded to the nearest whole*

Step-by-step explanation:

Because you are only given sides you can find an individual angle measures with the inverse law of cosines.

Remember the side opposite of the angle corresponds to that angle.

a² = b² + c² - 2bc cos(A) →

A = cos⁻¹ (a² - b² - c² / -2bc)

b² = a² + c² - 2ac cos(B) →

B = cos⁻¹ (b² - a² - c² / -2ac)

c² = a² + b² - 2ab cos(C) →

C = cos⁻¹ (c² - a² - b² / -2ab)

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Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

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\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}

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