How to find the x intercept of 3y=2x-6: (when y is 0)
3(0) = 2x - 6
0 = 2x - 6
+6 + 6
-------------------------
6 = 2x
------ -----
2 2
x = 3
How to find the y intercept of 3y=2x-6: (when x is 0)
3y = 2(0) - 6
y = 0 - 6
3y = -6
------ -----
3 3
y = -2
A)
It looks like the [irregular] hexagon has 3 rectangles and 2 triangles within it.
So let's exclude the triangular corners on bottom left and top right for now.
First we have a large rectangle covering most of the upper left of the polygon. 20 ft × 7 ft = 140 sq.ft.
Now we have a rectangle on the bottom right. The width is 11 ft, so take the 7 away from that, 4 ft. × 14 ft. on bottom. 4 ft × 14 ft = 56 sq.ft.
The last small rectangle fits on the right between the 2 other rectangles. It is 24-20 on top/bottom × 7-6 right/left. 4 ft × 1 ft = 4 sq.ft.
Now for the triangles: bottom left is 11-7 × 24-14 = 4 ft × 10 ft. 1/2bh = 1/2×10×4 = 20 sq.ft.
Top right is 24-20 × 11-5 = 4 ft × 6 ft. 1/2bh = 1/2×4×6 = 12 sq.ft.
B)
Add them all together for the total area (A):
A = 140 + 56 + 4 + 20 + 12 = 140+60+32
= 232 sq.ft.
Hope that explains it well enough! ;)
Universe exploded into existence
Answer:
b
Step-by-step explanation:
The inscribed angle 36°m is half the measure of its intercepted arc, that is
b = 2 × 36 = 72
c = 360 - (108 + 72) = 360 - 180 = 180 ( total sum of arcs in a circle )
The angle between a tangent and the radius of a circle at the point of contact is 90° , then
d = 90
Thus b = 72, c = 180, d = 90 → b
