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2 years ago

Can somebody help me on question 15?!

Mathematics

2 answers:

Bess [88]2 years ago

6 0

Answer: better value is the 1st box

Step-by-step explanation:

1st box= $0.75 per choc

2nd box= $0.8 per choc

Ivenika [448]2 years ago

4 0

1st answe is corrective

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How do you solve this 13c<-169

Bess [88]

The answer is c < -13

6 0

2 years ago

I am a 2-digit number. The sum of my digits is 16. My ten’s digit is greater than my one’s digit. What number am I?

jarptica [38.1K]

Answer:

Step-by-step explanation:8? 8 is greater than 0 xd

8 0

2 years ago

What are the roots of the quadratic equation 2x2+7x+4=0? Select all that apply.

skad [1K]

Answer:

option A and B

$x=\frac{-7+\sqrt{17}} {4}$

and

$x=\frac{-7-\sqrt{17}} {4}$

Step-by-step explanation:

we have

$2x^2+7x+4=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^2+7x+4=0$

$a=2\\b=7\\c=4$

substitute in the formula

$x=\frac{-7\pm\sqrt{7^{2}-4(2)(4)}} {2(2)}$

$x=\frac{-7\pm\sqrt{17}} {4}$

$x=\frac{-7+\sqrt{17}} {4}$

and

$x=\frac{-7-\sqrt{17}} {4}$

7 0

2 years ago

Write the equation of the line that passes through the points (3,5) and (-1,1). Put

dangina [55]

Given:

A line passes through the two points (3,5) and (-1,1).

To find:

The equation of the line in fully reduced point-slope form.

Solution:

If a line passes through two points, then the point slope form of the line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

The line passes through the two points (3,5) and (-1,1). So, the point slope form of the line is

$y-5=\dfrac{1-5}{-1-3}(x-3)$

$y-5=\dfrac{-4}{-4}(x-3)$

$y-5=1(x-3)$

Therefore, the point slope form of the line in fully reduced form is $y-5=1(x-3)$ , here 1 is the slope of the line.

6 0

3 years ago

Y = 5-3x, Darw the graph of the function. Use the find the value of y when x=4, and when x = 5

stellarik [79]

Answer:

The line passes through (4, -7) and (5, -10).

Step-by-step explanation:

When x = 4, y = 5 - 3(4), or 5 - 12, or -7. Thus the point (4, -7) lies on the graph. Similarly y = 5 - 3(5) = -10 when x = 5. Thus, the line also goes through (5, -10). Plot these two points and draw a line through them. Doing this will result in the desired graph.

6 0

2 years ago