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alexandr402 [8]
4 years ago
10

Element X decays radioactively with a half life of 13 minutes. If there are 110 grams of Element X, how long, to the nearest ten

th of a minute, would it take the element to decay to 2 grams?
Mathematics
1 answer:
Vaselesa [24]4 years ago
7 0

Answer : The time taken by the element to decay to 2 grams is, 75.2 minutes

Step-by-step explanation:

Half-life = 13 min

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{13\text{ min}}

k=0.0533\text{ min}^{-1}

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 0.0533\text{ min}^{-1}

t = time passed by the sample  = ?

a = initial amount of the reactant  = 110 g

a - x = amount left after decay process =  2 g

Now put all the given values in above equation, we get

t=\frac{2.303}{0.0533}\log\frac{110}{2}

t=75.2\text{ min}

Therefore, the time taken by the element to decay to 2 grams is, 75.2 minutes

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Answer:

The width of the pathway is:

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Step-by-step explanation:

To identify the width of the pathway, you must remember the area formula of a rectangle:

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From which the width can be cleared:

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We know that the length of the terrain was not modified since the pathway is in the perimeter of the rectangle (16 m) and that the new area is 240 m^2, so we only have to replace the cleared formula:

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The new width is equal to 15 meters, but since the question is not the total width but the width of the pathway, the width of the previously provided land must be subtracted from the value obtained.

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N P r = (n!)/((n-r)!)
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