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elena-14-01-66 [18.8K]
2 years ago
11

Simplify.

rt16+ \sqrt8" alt="\sqrt32 + \sqrt16+ \sqrt8" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
svetoff [14.1K]2 years ago
5 0

Answer:

4 + 6 \sqrt{2}

Step-by-step explanation:

\sqrt{32}  +  \sqrt{16}  +  \sqrt{8}

\sqrt{32}  =  \sqrt{4 \times 4 \times 2}  =  4\sqrt{2}

\sqrt{16}  =  \sqrt{4 \times 4}  = 4

\sqrt{8}  =  \sqrt{2 \times 2 \times 2}  = 2 \sqrt{2}

4 +  4\sqrt{2}  + 2 \sqrt{2}  = 4 + 6 \sqrt{2}

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Read 2 more answers
143=7+8(3-7x) solve and justify
Llana [10]
Justify means plug answer in and verify

so distribute 8(3-7x)=24-56x

143=7+24-56x
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minus 31 both sides
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divide both sides by -56
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plug it back
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3 years ago
Describe the end behavior of the graphed function
Troyanec [42]

You have to consider the “ends” of the x-axis, the far right (for infinitely large values of x) and left (for infinitely small values of x) of the graph.

From the diagram above you can see that:

  1. When x\rightarrow -\infty, then y=f(x)\rightarrow 1 (notice that as the values of x get smaller and smaller, the graph gets closer and closer to the line y=1);
  2. When x\rightarrow \infty, then y=f(x)\rightarrow 1. (notice that as the values of x get larger and larger, the graph gets closer and closer to the line y=1).

Answer: correct choice is D.

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An individual who has automobile insurance from a certain company is randomly selected. Let X be the number of moving violations
grin007 [14]

Answer:

(X)      0        1          2          3         4

P(X)   0.17   0.23    0.27    0.24    0.09

F(x)    0.17    0.04    0.65    0.91      1      

Step-by-step explanation:  

Given that;

(X)      0        1          2          3         4

P(X)   0.17   0.23    0.27    0.24    0.09

cumulative distribution function can be calculated by;  be cumulatively up the value of p(x) with the values before it;

so

x      F(x)

0     P(X = 0) = 0.17

1       P(X = 0) + P(X = 1) = 0.17 + 0.23 = 0.4

2      P(X = 0) + P(X = 1) + P(X = 2) = 0.17 + 0.23 + 0.27 = 0.65

3      P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.17 + 0.23 + 0.27 + 0.24 = 0.91

4      P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.17 + 0.23 + 0.27 + 0.24 + 0.09 = 1

Therefore, cumulative distribution function f(x) is;

(X)      0        1          2          3         4

P(X)   0.17   0.23    0.27    0.24    0.09

F(x)    0.17    0.04    0.65    0.91      1      

8 0
2 years ago
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