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elena-14-01-66 [18.8K]
2 years ago
11

Simplify.

rt16+ \sqrt8" alt="\sqrt32 + \sqrt16+ \sqrt8" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
svetoff [14.1K]2 years ago
5 0

Answer:

4 + 6 \sqrt{2}

Step-by-step explanation:

\sqrt{32}  +  \sqrt{16}  +  \sqrt{8}

\sqrt{32}  =  \sqrt{4 \times 4 \times 2}  =  4\sqrt{2}

\sqrt{16}  =  \sqrt{4 \times 4}  = 4

\sqrt{8}  =  \sqrt{2 \times 2 \times 2}  = 2 \sqrt{2}

4 +  4\sqrt{2}  + 2 \sqrt{2}  = 4 + 6 \sqrt{2}

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3 years ago
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Step-by-step explanation:

5 0
3 years ago
An electronics company packages its product in cube-shaped boxes. These boxes are placed into a larger box that measures 3 ft lo
gladu [14]

The number of boxes fitted in the larger container is found out by the volume of both boxes.

The number of boxes fitted into the larger container is 480.

<h3>What is the volume?</h3>

The volume can be defined as the space occupied by an object in three dimensions.

Given that the edge of the cube box is 1/4 ft. The dimensions of the larger box are 3 ft long, 1 1/4 ft wide, and 2 ft.

The volume of the cube box is calculated as given below.

V_s = s^3

Where Vs is the volume of the cube box and s is the edge of the cube box.

V_s = \dfrac {1}{4}^3

V_s = 0.015625\;\rm ft^3

The volume of the larger box is calculated as given below.

<em />V = l \times w\times h

Where V is the volume, l is length, w is width and h is the height of the larger box.

V = 3 \times \dfrac {5}{4} \times 2

V = 7.5\;\rm ft^3

The number of cube boxes fitted into the larger box is calculated as given below.

No. \; of \;boxes = \dfrac {V}{V_s}

No. \; of \;boxes = \dfrac {7.5}{0.015625}

No. \; of \;boxes = 480

Hence we can conclude the number of boxes fitted into the larger container is 480.

To know more about the volume, follow the link given below.

brainly.com/question/1578538.

8 0
2 years ago
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svetoff [14.1K]

Answer:

option C. is correct answer it is 2/5

6 0
3 years ago
Read 2 more answers
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jenyasd209 [6]
B! Would be the answer! Good luck on the test!
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3 years ago
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