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elena-14-01-66 [18.8K]

2 years ago

11

Simplify.

rt16+ \sqrt8" alt="\sqrt32 + \sqrt16+ \sqrt8" align="absmiddle" class="latex-formula">

1 answer:

svetoff [14.1K]2 years ago

5 0

Answer:

$4 + 6 \sqrt{2}$

Step-by-step explanation:

$\sqrt{32} + \sqrt{16} + \sqrt{8}$

$\sqrt{32} = \sqrt{4 \times 4 \times 2} = 4\sqrt{2}$

$\sqrt{16} = \sqrt{4 \times 4} = 4$

$\sqrt{8} = \sqrt{2 \times 2 \times 2} = 2 \sqrt{2}$

$4 + 4\sqrt{2} + 2 \sqrt{2} = 4 + 6 \sqrt{2}$

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Amelia must substitute 8 for the variable using parentheses. To simplify, Amelia must multiply 8 by 6. 8 is not a solution of the equation.

<h3>What is algebraic expression?</h3>

Algebraic expression are the expression which consist the variables, coefficients of variables and constants.

The algebraic expression are used represent the general problem in the mathematical way to solve them.

Amelia is using substitution to determine if 8 is a solution to the equation. The equation which is Amelia is solving for a = 8 is,

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First, Amelia must substitute 8 for the variable using parentheses as,

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Step-by-step explanation:

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2 years ago

2x + y - z = -8

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Answer:

Multiply row 1 by $\frac{1}{2}$ .

Step-by-step explanation:

The augmented matrix of the system of linear equation is described below:

$\left[\begin{array}{cccc}2&1&-1&-8\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]$

Where $a_{11} = 2$ , if we need to create $a_{11} = 1$ , we need to multiply row 1 by $\frac{1}{2}$ , that is to say:

$\left[\begin{array}{cccc}1&\frac{1}{2} &-\frac{1}{2} &-4\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]$

Hence, the correct answer is: Multiply row 1 by $\frac{1}{2}$ .

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3 years ago