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emmainna [20.7K]
2 years ago
8

Find the greatest common factor of 15x^6 and 33x^4y^5

Mathematics
2 answers:
Katena32 [7]2 years ago
5 0

Answer:

495x^10 y^5

Step-by-step explanation:

zhannawk [14.2K]2 years ago
4 0

Answer:

3x^4

Step-by-step explanation:

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( ONLY ANSWER THIS IF YOU KNOW WHAT THE ANSWER IS) I will give Brainliest!
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Answer:

?

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3 years ago
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3 years ago
Solve the system of linear equations. separate the x- and y- values with a coma. -5x+6y=33 -18x+4y=-22
Pavel [41]
I hope I can help you:)

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1 year ago
Mathswatch Question! Mr Powers checks his electricity bill. Here are his meter readings. New reading: 6538 units, Old reading: 6
Setler79 [48]

Answer:

Cost = 284 x

Step-by-step explanation:

Given

Old = 6245\ units

New = 6538\ units

Required

The cost of units used

First, calculate the number of units used.

Units = New - Old

Units = 6538 - 6254

Units = 284

Next, multiply the units used by the cost per units,

Since the cost per unit is not given, we assume that it is x.

So, the total cost is:

Cost = Units * Cost\ per\ units

Cost = 284 * x

Cost = 284 x

3 0
3 years ago
If a = √3-√11 and b = 1 /a, then find a² - b²​
Serga [27]

If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

Now,

a^2 - b^2 = (a-b) (a+b)

and

a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8

a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8

\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

5 0
1 year ago
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