Question

Find an equation of the line that passes through the point (2, -8) and is perpendicular to the line 2x-6y=10

Answer 1

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Answer:

  3x +y = -2

Step-by-step explanation:

First of all, it is helpful to put the given equation in standard form. We can do that by dividing it by 2 to eliminate the common factor from the numbers.

  x -3y = 5

Next, since you want the perpendicular line, you can swap the coefficients of x and y, and negate one of them. This can give you ...

  3x +y = (some constant)

The constant will be found using the given point.

  3x +y = 3(2) +(-8) = -2 . . . the perpendicular line

An equation is ...

  3x +y = -2