Find an equation of the line that passes through the point (2, -8) and is perpendicular to the line 2x-6y=10
1 answer:
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Answer:
3x +y = -2
Step-by-step explanation:
First of all, it is helpful to put the given equation in standard form. We can do that by dividing it by 2 to eliminate the common factor from the numbers.
x -3y = 5
Next, since you want the perpendicular line, you can swap the coefficients of x and y, and negate one of them. This can give you ...
3x +y = (some constant)
The constant will be found using the given point.
3x +y = 3(2) +(-8) = -2 . . . the perpendicular line
An equation is ...
3x +y = -2
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