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Mrrafil [7]
3 years ago
7

Are the following lines parallel ?

Mathematics
2 answers:
Zarrin [17]3 years ago
4 0

Answer:

false jfkdigitkhijdkdkcjgjdjjbkdkvkffkb

umka2103 [35]3 years ago
4 0
True it’s not gonna intercept
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n your computer store you charge $1012 per computer sold. Your costs are given by the equation C(x) = 4x^2 + 4x - 80 where x is
ella [17]

Answer:

63568 dollars

Step-by-step explanation:

Given that in your computer store you charge $1012 per computer sold. Your costs are given by the equation

C(x) = 4x^2 + 4x - 80

where x is the number of computers sold.

Revenue = sales price *no of computers sold

= 1012x

Profit = Revenue - cost

= 1012x-( 4x^2 + 4x - 80)\\= 1008x-4x^2+80\\

Use derivative test to find maximum profit

C'(x) = 1008-8x \\C''(x)= -x

Equate I derivative to 0

x= 128

i.e. if 128 computers are manufactured and sold profit wouldbemaximum

Profit maximum=1008(128)-4(128)^2+80\\=63568

3 0
4 years ago
Solve the system of equations
agasfer [191]
D<span>here, we go by the same exact principle, but the terms are not a,b,c.
</span>
8 0
3 years ago
Work out the volume of the shape​
pashok25 [27]

Answer:

\large\boxed{V=\dfrac{1,421\pi}{3}\ cm^3}

Step-by-step explanation:

We have the cone and the half-sphere.

The formula of a volume of a cone:

V_c=\dfrac{1}{3}\pi r^2H

r - radius

H - height

We have r = 7cm and H = (22-7)cm=15cm. Substitute:

V_c=\dfrac{1}{3}\pi(7^2)(15)=\dfrac{1}{3}\pi(49)(15)=\dfrac{735\pi}{3}\ cm^3

The formula of a volume of a sphere:

V_s=\dfrac{4}{3}\pi R^3

R - radius

Therefore the formula of a volume of a half-sphere:

V_{hs}=\dfrac{1}{2}\cdot\dfrac{4}{3}\pi R^3=\dfrac{2}{3}\pi R^3

We have R = 7cm. Substitute:

V_{hs}=\dfrac{2}{3}\pi(7^3)=\dfrac{2}{3}\pi(343)=\dfrac{686\pi}{3}\ cm^3

The volume of the given shape:

V=V_c+V_{hs}

Substitute:

V=\dfrac{735\pi}{3}+\dfrac{686\pi}{3}=\dfrac{1,421\pi}{3}\ cm^3

7 0
3 years ago
For a standard normal distribution, find the approximate value of P(-0.78 = z = 1.16). Use the portion of the standard normal ta
VikaD [51]

Correction:

I think the question should be like that find the approximate value of

P(-0.78 < z < 1.16)?


Now,

the symbol Ф represent the cumulative density.

first find the

Ф(1.16) from the above given table which is equal to 0.8770.

Now,

find the Ф(-0.78) .

in our table we are given the value of Ф(0.78)=0.7823

so as the curve is symmetrical Ф(-0.78)=1-0.7823=0.2177


P(-0.78 < z < 1.16) = Ф(1.16)-Ф(-0.78)

= 0.8770-0.2177

= 0.6593

6 0
3 years ago
Read 2 more answers
I need help. this is the problem x^2/3+10=7x^1/3
Arlecino [84]

\it x^{\frac{2}{3}}+10=7x^{\frac{1}{3}} \Leftrightarrow  (x^{\frac{1}{3}})^2-7x^{\frac{1}&#10;  {3}} +10=0 &#10;\\\;\\&#10;We\ note\ x^{\frac{1}{3}} =t \ \ and \ the \ equation \ will \ be:&#10;\\\;\\&#10;t^2-7t+10 = 0 \Leftrightarrow t^2 -2t-5t+10=0 \Leftrightarrow t(t-2) -5(t-2)=0

\it \Leftrightarrow (t-2)(t-5)=0 &#10;\\\;\\&#10;t-2=0 \Rightarrow t=2 \Rightarrow x^{\frac{1}{3}}=2 \Rightarrow (x^{\frac{1}{3}})^3 =2^3 \Rightarrow x = 8&#10;\\\;\\&#10;t-5=0 \Rightarrow t=5 \Rightarrow x^{\frac{1}{3}}= 5  \Rightarrow (x^{\frac{1}{3}})^3 = 5^3 \Rightarrow x = 125

S = {8; 125}


7 0
4 years ago
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