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BlackZzzverrR [31]
3 years ago
6

(6x – 10y + 12) – 3

Mathematics
1 answer:
Margarita [4]3 years ago
8 0

6x-10y+9

Step-by-step explanation:

(6x – 10y + 12) – 3

6x-10y+12-3

subtract 12-3

6x-10y+9

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Need help with #11. The answer is about 13.86 years but show work please.
tangare [24]

Answer:

13.86

Step-by-step explanation:

formula for cont. compounding interest is

Amount = Principal * e^rt

in this case the principal is 5000, and the amount is 10000 (double). the rate is 5% or 0.05. and t is what we are solving for.

sub in to get:

10000 = 5000e^0.05t

2 = e^0.05t

now convert to log form.

ln 2 = 0.05t

ln 2 / 0.05 = t

punch that into your calculator and you get 13.86 years

6 0
3 years ago
write the converse, inverse and contrapositive of the following sentences. if the sun shines Bright today, then it will set earl
KIM [24]

Answer:

If the converse is true, then the inverse is also logically true. If two angles are congruent, then they have the same measure.

...

Converse, Inverse, Contrapositive.

Statement If p , then q .

Converse If q , then p .

Inverse If not p , then not q .

Contrapositive If not q , then not p .

8 0
3 years ago
Rema spent 6 days reading her book, completing the same fraction of the book each day, if she read a total of 8/9 of her book af
AnnZ [28]
(8/9) / 6 =
8/9 * 1/6 =
8/54 which reduces to 4/27 of the book each day <===
7 0
3 years ago
Two kilograms of bronze costs £7.20<br> What is the cost of 300g of bronze
sineoko [7]
We know that
1 Kg is equals to--------------> 1000 g
so
 X Kg------------------------> 300 g
X=300/1000------> x=0.30 Kg

if  2 Kg cost--------------> <span>£7.20
  0.30 Kg-------------> X
X=0.30*7.20/2------> x=1.08

the answer is 
</span>£1.08
3 0
3 years ago
1 point
swat32

Answer:

\log_{10}(147) = 2.1673

Step-by-step explanation:

Given

\log_{10} 3 = 0.4771

\log_{10} 5 = 0.6990

\log_{10} 7= 0.8451

\log_{10} 11 = 1.0414

Required

Evaluate \log_{10}(147)

Expand

\log_{10}(147) = \log_{10}(49 * 3)

Further expand

\log_{10}(147) = \log_{10}(7 * 7 * 3)

Apply product rule of logarithm

\log_{10}(147) = \log_{10}(7) + \log_{10}(7) + \log_{10}(3)

Substitute values for log(7) and log(3)

\log_{10}(147) = 0.8451 + 0.8451 + 0.4771

\log_{10}(147) = 2.1673

3 0
3 years ago
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