All categories

3 years ago

How do you work out 8x+3=8×+27

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

4 0

Answer:

No solution

Step-by-step explanation:

8x + 8 = 8x + 27

You then cancel out the 8s. 8 - 8 = 0

Which leaves you with 8 = 27...

Since this is an untrue statement, the answer would be no solution, unless you typed it wrong.

You might be interested in

Long division 7÷688 remainder of what and the answerand what steps how to do it

nadya68 [22]

Here are the steps on how I did it.

6 0

3 years ago

The probability that your call to a service line is answered in less than 30 seconds is 0.85. Assume that your calls are indepen

aev [14]

Answer:

a) 0.1720

b) 0.8298

c) 19

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.85$

(a) If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X = 9)$ when $n = 12$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{12,9}.(0.85)^{9}.(0.15)^{3} = 0.1720$

(b) If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X \geq 16)$ when $n = 20$

$P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 16) = C_{20,16}.(0.85)^{16}.(0.15)^{4} = 0.1821$

$P(X = 17) = C_{20,17}.(0.85)^{17}.(0.15)^{3} = 0.2428$

$P(X = 18) = C_{20,18}.(0.85)^{18}.(0.15)^{2} = 0.2293$

$P(X = 19) = C_{20,19}.(0.85)^{19}.(0.15)^{1} = 0.1368$

$P(X = 20) = C_{20,20}.(0.85)^{20}.(0.15)^{0} = 0.0388$

$P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1821 + 0.2428 + 0.2293 + 0.1368 + 0.0388 = 0.8298$

(c) If you call 22 times, what is the mean number of calls that are answered in less than 30 seconds? Round your answer to the nearest integer.

The expected value of the binomial distribution is:

$E(X) = np$

In this question, we have $n = 22$

$E(X) = 22*0.85 = 18.7$

The nearest integer to 18.7 is 19.

7 0

3 years ago

Find all the real square roots of -196.

Slav-nsk [51]

The answer is <span>-(3/4) and 3/4</span>

6 0

3 years ago

Avery’s piggy bank has 300 nickels, 450 pennies, and 150 dimes. She randomly picks three coins. Each time she picks a coin, she

Mashutka [201]

Answer:

(1) .20 (2) .40 (3) .12 (4) Less than

Step-by-step explanation:

You have to look at the table. There are 5 columns with 10 rows. 5x10=50

Then simply count the boxes that have the correct number of currency for instance, if they are asking for EXACTLY 1 dime then you rule out the ones that have 2 or 3 dimes and only the count the ones that have a single dime. So you count PDN but you would not count PDD. There are 20 boxes that have a single dime in them. 20 out of the 50 boxes. 20/50=.40 (answer 2)

The estimated probability that exactly two of the three coins Avery randomly picked are nickels is . 20

The estimated probability that exactly one of the three coins Avery randomly picked is a dime is . 40

The estimated probability that all three coins Avery randomly picked are pennies is . 12

The answer to #1 is .20 or 20% and the answer to #2 is .40 or 40%. 20% is less than 40% so...

The estimated probability that exactly two of the three coins Avery randomly picked are nickels is LESS THAN the estimated probability that exactly one of the three coins Avery randomly picked is a dime.

4 0

3 years ago

When you don't know the answer on a multiple-choice questions it is generally best to

cluponka [151]

When you don't know the answer on a multiple-choice questions it is generally best to guess a random answer instead of leaving it blank.
Can you follow me and like me please? I hope i can help you more.☺

5 0

3 years ago

Read 2 more answers