<span>A. H(w) gets very large. </span>
Answer:
(10, - 9 )
Step-by-step explanation:
Given the 2 equations
y = - 2x + 11 → (1)
y = - 3x + 21 → (2)
Substitute y = - 2x + 11 into (2)
- 2x + 11 = - 3x + 21 ( add 3x to both sides )
x + 11 = 21 ( subtract 11 from both sides )
x = 10
Substitute x = 10 into either of the 2 equations and evaluate fir y
Substituting into (1)
y = - 2(10) + 11 = - 20 + 11 = - 9
solution is (10, - 9 )
I believe it is -8y + 5x - 3
Let's see what the options look like when we multiply the expressions in brackets:
(first, i multiply both parts of the second bracked by the first part of the first bracket, and then the same with the second part of the first bracket:
<span>(1) (3x - 3)(x - 2))
3x2 +6x -3x +6// this is not correct
(2) (3x + 3)(x - 2) </span>
3x2-6x+3x-6//this is not correct
(3)
3(x + 1)(x - 2)
3(x2-2x+x-2)//simplifying:
3(x2-x-2)//multiplying:
3x2-3x-6)
- so this is not correct either
(4) 3(x - 1)(x - 2)
3(x2-2x - x + 2)
3(x2-3x +2)
3x2-9x +6 - well, here is our winner!
Answer:
Step-by-step explanation:
We know that for two similar matrices and exists an invertible matrix for which
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∴
Also
and
∴
so,