Answer:
(B)The GCF of the numbers(28 and 36) in each term in the expression is 4.
(C)The GCF of the variables(a and ab) in each term in the expression is a.
(E)The factored form of the expression is 4a(7+9b)
Step-by-step explanation:
Given the expression: 
If we write it as a product, we obtain:
We can see the following
- The GCF of the numbers(28 and 36) in each term in the expression is 4.
- The GCF of the variables(a and ab) in each term in the expression is a.
- The factored form of the expression is 4a(7+9b)
The correct options are B, C, and E.
Answer:
a) P ( 3 ≤X≤ 5 ) = 0.02619
b) E(X) = 1
Step-by-step explanation:
Given:
- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:
Find:
a.Calculate the probability that 3 ≤X≤ 5
b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that
Solution:
- The CDF gives the probability of (X < x) for any value of x. So to compute the P ( 3 ≤X≤ 5 ) we will set the limits.
- The Expected Value can be determined by sum to infinity of CDF:
E(X) = Σ ( 1 - F(X) )
E(X) = Limit n->∞ [1 - 1 / ( n + 2 ) ]
E(X) = 1
are there multiple choice answers because i can help with those.
