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Jlenok [28]
3 years ago
7

In the isosceles trapezoid LMNO, find the value of x.

Mathematics
1 answer:
zmey [24]3 years ago
7 0

Answer:

15 would be the correct answrr

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Vera_Pavlovna [14]
So i think u subtract how much money the person got and then subtract the answer by his pay.
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3 years ago
Find the missing numerical value in the box for which the equation 2/3(6x−12)=8+□(2x−4) has no solution.
Aloiza [94]

Answer:

23

Step-by-step explanation:

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3 years ago
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The cost of coffee is determined by the type of coffee beans that are mixed together. The cost of a local mix of Arabica and Rob
guapka [62]
700a+1200r=1000000       (then plug in the a)
700(1000) +1200r=1000000        (simplify)
700000+1200r=1000000        (subtract 700000 from both sides)
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it is known that the population proton of utha residnet that are members of the church of jesus christ 0l6 suppose a random samp
Lady_Fox [76]

Answer:

0.0838 = 8.38% probability of obtaining a sample proportion less than 0.5.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Proportion of 0.6

This means that p = 0.6

Sample of 46

This means that n = 46

Mean and standard deviation:

\mu = p = 0.6

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.6*0.4}{46}} = 0.0722

Probability of obtaining a sample proportion less than 0.5.

p-value of Z when X = 0.5. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.5 - 0.6}{0.0722}

Z = -1.38

Z = -1.38 has a p-value of 0.0838

0.0838 = 8.38% probability of obtaining a sample proportion less than 0.5.

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3 years ago
What numbers can be rounded to 360 when rounded to the nearest ten
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355, and any greater number that's less than 365, can.
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