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Jlenok [28]
3 years ago
7

In the isosceles trapezoid LMNO, find the value of x.

Mathematics
1 answer:
zmey [24]3 years ago
7 0

Answer:

15 would be the correct answrr

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sukhopar [10]
There are 10 total marbles and three are pink. So you are to determine the probability of choosing a pink marble, placing it back in the bag and choosing another pink marble.
The probability of choosing a pink marble is # of pink marbles to # of all marbles which is 3/10. Since we place the marble back in the bag, the probability is the same for the second time.
To determine the probability of both occurrences, we need to multiply 3/10 x 3/10 which is 9/100. This can be written as 9:100 as a ratio.
4 0
3 years ago
Mr.Kent interviewed 54 students as they left the school. Is this a random sample? Explain. I will give Brainliest and please ans
malfutka [58]

Answer:

Hello there! :) This is not a random sample becuase the 54 students are'nt chosen at random.

Step-by-step explanation:

These students are pre-chosen by Mr. Kent, meaning that he could have biased whatever he was interviewing them on. And it does not mention anything like, the first 54 students to leave or the last 54 students to leave. I hope this helps!

7 0
3 years ago
21
Tju [1.3M]

Answer:

64x^127

Step-by-step explanation:

caculate it with all the numb

3 0
2 years ago
Which of the following are steps to use when formulating an equation? Check all that apply.
Ber [7]

Answer:

A and B

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Are you getting enough sleep? Many kids aren’t getting enough sleep, and TV might be part of the problem. Among 2002 randomly se
Naya [18.7K]

Using the z-distribution, it is found that the lower bound of the 99% confidence interval is given by:

d. 68.39%.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 99% confidence level, hence\alpha = 0.99, z is the value of Z that has a p-value of \frac{1+0.99}{2} = 0.995, so the critical value is z = 2.575.

The sample size and estimate are given by:

n = 2002, \pi = 0.71

Hence, the lower bound is given by:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.71 - 2.575\sqrt{\frac{0.71(0.29)}{2002}} = 0.6839

Hence the lower bound is of 68.39%, which means that option D is correct.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0
3 years ago
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