6 out of every 10 student would be girls given that 100 of the students are boys awnser = 3/5
Fisrt is solve the distance of the segments using distance
formula
Distance =sqroot[(x2−x1)^2+(y2−y1)^2]
So ditance of RS = 5
ST = 8.49
TR =6.08
The using herons formula
Area = sqrt ( s ( s-a) ( s-b) ( s-c) )
Where s s = 1/2 ( a + b + c )
And a, b , c are length of the sides
S = 9.785
Area = 14.99
Answer:
The length of a rectangle is 5 centimetres longer than twice its width. If the perimeter of the rectangle is 88 centimetres, what is the width?
width=x
length=2x+5
perimeter=88=2L+2W
so half perimeter=44=L+W
x+2x+5=44
3x=39
x=13 cm width ANSWER
2x+5=31 cm length
Set R(x) equal to C(x). Solve the resulting equation for x, paying attention to the domain of C(x):
Solve 200x-2x^2 = -x^2 + 25x + 31000 for x greater than or equal to zero but less than or equal to x. That means you must reject any solution outside of this domain.
Rearrange all of these terms on the left side of your equation and place zero on the right side. Next, rearrange all of the terms on the left side in descending order by powers of x. Next, solve the resulting quadratic equation. Make certain to reject any x that does not fall within [0,100].
A rational number<span> is a </span>number<span> that can be written as a ratio.</span>
